Proving Integral Domain of D Using Commutative Ring

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Homework Help Overview

The problem involves demonstrating that a given commutative ring D is an integral domain by showing that there are no zero divisors, based on the condition that if ab = ac for a non-zero a, then b must equal c.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the implications of the given condition and explore the contrapositive approach. Some question whether assuming D is not an integral domain is a valid method, while others suggest examining cases where b and c may differ.

Discussion Status

The discussion is ongoing, with participants offering different perspectives on how to approach the proof. Some guidance has been provided regarding the implications of the initial condition, but no consensus has been reached on a specific method or direction.

Contextual Notes

There is mention of potential examples, such as Z mod 6, to illustrate cases of zero divisors, indicating that participants are considering specific instances to understand the general case.

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Homework Statement


Given a,b,c in D, with a not 0, we have ab=ac implies b=c. Show that the commutative ring D is an integral domain.

The Attempt at a Solution


I don't know where to begin with this.
 
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You want to show that there are no 0 divisors. Look at what's given. Look at its contrapositive.
 
So we want to assume it is not an integral domain, then show that b does not equal c?

Well, I know it is possible for b to not equal c because if we are in say, Z mod 6, then [0]=[3]=[6]. But how do I generalize this? Is this the right method to go about it?
 
You don't have to prove by contradiction. What I meant was that since we have

a [tex]\ne[/tex] 0, ab = ac implies b = c,

we also know

a [tex]\ne[/tex] 0, b [tex]\ne[/tex] c implies ab [tex]\ne[/tex] ac. Letting b = 0 or c = 0 should get you what you want.
 
I think Michael would be ashamed
 

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