Proving Internal Pressure of Ideal & VdW Gases

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SUMMARY

The internal pressure of an ideal gas is definitively zero, as established by the equation (∂U/∂V) for constant T. For a Van der Waals gas, the internal pressure is calculated as (n²a)/(v²), derived from the Van der Waals equation p = (nRT)/(v-b) - (n²a)/(v²). The relationship between internal pressure and the caloric equation of state is crucial for understanding these concepts. The derivation involves using Maxwell's relations and the thermal equation of state.

PREREQUISITES
  • Understanding of thermodynamic equations of state, specifically for ideal and Van der Waals gases.
  • Familiarity with partial derivatives in thermodynamics, particularly (∂U/∂V) for constant T.
  • Knowledge of the relationship between internal energy (U) and entropy (S).
  • Basic grasp of Maxwell's relations in thermodynamics.
NEXT STEPS
  • Study the derivation of the caloric equation of state for ideal gases.
  • Learn about the implications of Maxwell's relations in thermodynamics.
  • Explore the applications of the Van der Waals equation in real gas behavior.
  • Investigate the relationship between internal energy and pressure in various thermodynamic systems.
USEFUL FOR

Students and professionals in thermodynamics, particularly those studying gas laws and internal energy calculations. This discussion is beneficial for anyone seeking to deepen their understanding of ideal and Van der Waals gases.

Jennifer Lyn
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Like in the other problem I posted- This is the other question that I missed and just can't find a solution for.

Homework Statement


Prove the internal pressure is 0 for an ideal gas and ((n^2)a)/(v^2) for a Van der Waals gas.

Homework Equations


1. VdQ Eqn: p= (nRT)/(v-b) - ((n^2)a)/(v^2)
2. (partial S/partial V) for constant T = (partial p/partial T) for contant V.
3. dU = TdS - pdV
4. pi sub t (internal pressure) = (partial U/partial V) for constant T


The Attempt at a Solution



a) Ideal Gas
0 = (partial U/partial V) for const T
int 0 dv = int du
0 = int (TdS - pdV)
int p dv = int T ds
int (nRT/v) dv = int (Pv/nR) dS
nRT x int(1/V) dv = pv/nR x int 1 dS
... and I get kind of lost here, though I know that what I've already done is wrong.. :(

b) VdW gas
I actual have to get going to school, but I'll come back and type up what I've done (incorrectly :( for this part afterwards).
 
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Hello Jennifer,

I suppose you are given the so called thermal equation of state p=p(T,V,n) for both

the ideal gas

p=\frac{nRT}{V}

and the Van der Waals gas

p=\frac{nRT}{V-nb}-\frac{n^2a}{V^2}

The inner pressure \left(\frac{\partial U}{\partial V}\right)_T can be calculated after finding the so called caloric equation of state U=U(T,V,n) for both cases.

Another straightforward method would be to use the following identity which shows that the caloric and thermal equations of state are not independent of each other:

\left(\frac{\partial U}{\partial V}\right)_T=T\left(\frac{\partial p}{\partial T}\right)_V-p

Do you know how to derive this identity?
 
I think so..
\Pit = \partialu/\partialv for constant t
= ( 1/\partialv\times(Tds - pdv) )
= T \times (\partialp/\partialt) - p

I think that's right. I still don't know how to get from that Maxwell relation to the ideal gas and Van der Waals eqn, though.
 
Last edited:
Ok, I think I figured it out, from my previous post (sorry- I am still getting used to using the tools for math on this board) I replace the vanderwaals eqn into P in my partial p and then just solve from there.
 
Thanks everyone!
 

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