Proving Invertibility of A^TA with Linearly Independent Columns

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To prove that A^TA is invertible when A has linearly independent columns, one can analyze the dimensions and rank of the matrices involved. Since A has linearly independent columns, its rank is equal to n, which implies that A^TA also has full rank. A common approach is to assume that a column of A^TA is a linear combination of others, leading to a contradiction. Additionally, performing column operations can simplify the problem by transforming A into a special form. Understanding these concepts is crucial for demonstrating the invertibility of A^TA.
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Linear Algebra PLS HELP!

I need help on this problem and been trying to figure it out for awhile.
Let A be an m x n matrix with linearly independent columns. Show that A^TA is invertible.
anything will help. Thanks
 
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I assume you meant A^tA? Anyway, consider the size of that matrix to begin with, that's over half the solution right there. Ah and for future reference, maybe you should post questions like this in the other homework help forum since Linear Algebra is typically taught beyond calculus. Maybe there are some people who exclusively look in that thread to answer problems.
 
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What is the rank of A? What is the rank of A^tA?
 
I'm feeling stupid right now. Disregard my earlier suggestions--while they do work eventually, they are more trouble than they are worth. A good way to approach this problem is by considering what would happen if one of the columns of the product was a linear combination of the other columns, writing out what that would mean, and proceeding to a contradiction.
 
Disregard my earlier suggestions--while they do work eventually, they are more trouble than they are worth.
I don't think they're bad. I think you can make the problem much simpler by doing column operations to write A = A'C where C is the matrix representing the column operations, and A' is of a special form. Of course, it means you have to pick a good special form, but hey! Math is an art. :biggrin:
 
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Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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