If N is cyclic normal in G and H is a subgroup of N, is H normal in G?

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moont14263
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Please can someone help me to prove this
If N is a cyclic normal subgroup of G and H is a subgroup of N then H is normal in G.
 
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You'll need to use the following:

If x in N has order k, then gxg-1 also has order n.

So conjugation won't change the order of the elements, and order of the elements determine which subgroup the element will belong to (in cyclic groups).
 
Could you give me more hints because I am not that much in cyclic groups. Thank you.
 
Show that, if G is abelian and if n is a number, then [tex]G(n)=\{g\in G~\vert~g^n=e\}[/tex] is a subgroup of G.

Then show that, if G is cyclic, then all subgroups of G are of the form G(n).