Proving one Differentiation results to another

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Homework Help Overview

The problem involves proving a relationship between the nth derivative of the function (sin4x + cos4x) and a specific expression involving cos(4x + nπ/2). The subject area pertains to calculus, specifically differentiation and the properties of trigonometric functions.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand how to handle the nth derivative notation and seeks clarification on whether it should be treated as a higher-order derivative. Some participants suggest using mathematical induction as a potential method for proof.

Discussion Status

The discussion is ongoing, with some guidance provided regarding the use of mathematical induction. The original poster expresses understanding after receiving feedback, indicating a productive exchange of ideas.

Contextual Notes

There is a mention of needing to prove a specific equality involving derivatives, and the original poster is grappling with the implications of the nth derivative notation. The context suggests that there may be constraints related to the homework assignment's requirements.

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Homework Statement


I need in proving that the derivative (d^{n}/dx^{n})(sin4x + cos4x) = 4n-1 cos(4x + n\pi/2)


The Attempt at a Solution


I understand implicit differentiation in basic problems but I get stump with the n exponent in the differentiation symbol; am I suppose to treat it as a 2nd, 3rd, 4th ... etc derivative?
If that's so, how should I prove that the left equation equals the right one.

So far I got to: 4(cos3x - sin3x)
 
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If you want you could try proving it by mathematical induction.

dn/dxn means the nth derivative
 
For the "induction step" you need to prove that IF
d^n 4(sin^4 x+ cos^4 x)= 4^{n-1} cos(4x+ n\pi/2)
then
d^}{n+1} 4(sin^4 x+ cos^4 x)= 4^{n} cos(4x+ (n+1)\pi/2)
You should be able to do that just by differentiating the right hand side of the first equationl.
 
Thank you, I understand now.
 

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