Proving that the tail of a convergent series approaches zero

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show that if ## a_n ## is any sequence and m is any integer such that the series ## \displaystyle \sum_{n=m}^\infty a_n ## converges, then ## \displaystyle\lim_{k \to \infty} \sum_{n=k}^{\infty
} a_n = 0 ##

let ## S_N = \displaystyle \sum_{n=m}^N a_n ##

## \lim_{N \to \infty} S_N = l ## from definition
also,
## \lim_{N \to \infty} S_{N-1} = l ##

## S_N - S_{N-1} = a_N ##

## \lim_{N \to \infty} (S_N - S_{N-1}) = \lim_{N \to \infty}(S_N) - \lim_{N \to \infty} S_{N-1} = 0 ## then ## \lim_{N \to \infty} a_N = 0 ## i.e. ## \lim_{N \to \infty} \sum_{n=m}^N a_n = 0 \Rightarrow \lim_{k \to \infty} \sum_{n=k}^{\infty} a_n = 0 ##

as you can see I don't really know how to prove this statement, but I have attempted it.

Could someone show me how I can proceed to do the proof properly?
 
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synkk said:
show that if ## a_n ## is any sequence and m is any integer such that the series ## \displaystyle \sum_{n=m}^\infty a_n ## converges, then ## \displaystyle\lim_{k \to \infty} \sum_{n=k}^{\infty
} a_n = 0 ##

let ## S_N = \displaystyle \sum_{n=m}^N a_n ##

## \lim_{N \to \infty} S_N = l ## from definition
also,
## \lim_{N \to \infty} S_{N-1} = l ##

## S_N - S_{N-1} = a_N ##

## \lim_{N \to \infty} (S_N - S_{N-1}) = \lim_{N \to \infty}(S_N) - \lim_{N \to \infty} S_{N-1} = 0 ## then ## \lim_{N \to \infty} a_N = 0 ## i.e. ## \lim_{N \to \infty} \sum_{n=m}^N a_n = 0 \Rightarrow \lim_{k \to \infty} \sum_{n=k}^{\infty} a_n = 0 ##

as you can see I don't really know how to prove this statement, but I have attempted it.

Could someone show me how I can proceed to do the proof properly?

You are given that
[tex] \sum_{n=m}^\infty a_n[/tex]
converges. Thus you have
[tex] L = \sum_{n=m}^\infty a_n = S_{k-1} + \sum_{n = k}^{\infty} a_n[/tex]
so that
[tex] |L - S_{k-1}| = \left| \sum_{n = k}^{\infty} a_n \right|[/tex]
 
pasmith said:
You are given that
[tex] \sum_{n=m}^\infty a_n[/tex]
converges. Thus you have
[tex] L = \sum_{n=m}^\infty a_n = S_{k-1} + \sum_{n = k}^{\infty} a_n[/tex]
so that
[tex] |L - S_{k-1}| = \left| \sum_{n = k}^{\infty} a_n \right|[/tex]
how did you get ## L = \sum_{n=m}^\infty a_n = S_{k-1} + \sum_{n=k}^{\infty} a_n ##?
 
synkk said:
how did you get ## L = \sum_{n=m}^\infty a_n = S_{k-1} + \sum_{n=k}^{\infty} a_n ##?

They've just written it as a sum of two series.
 
I do not believe it is correct though.
It should read [itex]L=\sum_{n=0}^\infty a_n = S_{k-1}+\sum_{n=k}^\infty a_n[/itex].
This is to be seen from the definition of [itex]S_k = \sum_{n=0}^k a_n[/itex].

The final step in post #2 is correct. (Although I'm not entirely sure why the absolute value shows up, but it doesn't make any difference here)
 
JorisL said:
I do not believe it is correct though.
It should read [itex]L=\sum_{n=0}^\infty a_n = S_{k-1}+\sum_{n=k}^\infty a_n[/itex].
This is to be seen from the definition of [itex]S_k = \sum_{n=0}^k a_n[/itex].

Read the OP. We are told that [itex]\sum_{n=m}^\infty a_n[/itex] converges for some integer [itex]m[/itex]. In particular, we are not told that [itex]m[/itex] is positive. Therefore the OP's definition of [itex]S_k = \sum_{n=m}^{k} a_n[/itex] is correct.

However, in any event the behaviour of a finite number of terms at the beginning of a sequence does not affect convergence of the series.
 
My bad, sorry for the confusion.
But this doesn't change anything indeed.