ice109
- 1,707
- 6
given x<y and x,y,z are elements of R prove there exists at least one z such that x<z<y.
proof:
x<z<y -> z>x and y>z
by the fact that the reals are unbounded there is definitely at least one z such that z>x
now either z>y,z<y, or z=y by the order axioms.
so... do i just let z<y and then call it a day?
proof:
x<z<y -> z>x and y>z
by the fact that the reals are unbounded there is definitely at least one z such that z>x
now either z>y,z<y, or z=y by the order axioms.
so... do i just let z<y and then call it a day?