Proving the Ideal Status of K in R: I and J as Ideals in a Ring R

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SUMMARY

The discussion centers on whether the set K = {ab | a ∈ I, b ∈ J} forms an ideal in a ring R, given that I and J are ideals in R. The conditions for an ideal are outlined, and it is established that K is non-empty and satisfies the scalar multiplication condition. However, the participants express uncertainty regarding the closure under subtraction, particularly when examining the expression ab - cd for a, c ∈ I and b, d ∈ J. A suggestion is made to explore counterexamples to determine if K fails to be an ideal.

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Homework Statement


Let I and J be ideals in R. Is the set K = {ab|a is an element of I, b is an element of J} an ideal in R?

Homework Equations


Conditions for an ideal, I of a ring R;
(i)I is nonempty,
(ii)for any c,e ε I: c-eεI
(iii)for any c ε I, rεR: rc, cr ε I.

The Attempt at a Solution



Let a,bεK.

K is not empty since it contains 0.
K seems to satisfy condition (iii) since r(ab)=(ra)b, and raεI since I is an ideal. Then (ra)bεK.
Also, (ab)r=a(br), and since brεJ, a(br)εK.

But nothing jumps out at me when I examine ab - cd , where a,cεI and b,dεJ.

Is it possible this is not an ideal?

Thanks.
 
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Try finding a counterexample.
 

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