Proving the Non-Perfect Square Property of 4 Consecutive Positive Integers

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    2016
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SUMMARY

The product of four consecutive positive integers is never a perfect square. This conclusion is established through mathematical reasoning involving the properties of integers and their prime factorization. Specifically, the proof demonstrates that among any four consecutive integers, at least one integer is divisible by 2 and at least one is divisible by 4, ensuring that the product cannot yield a perfect square. The discussion highlights contributions from members kaliprasad and lfdahl, who provided correct solutions to the problem.

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Here is this week's POTW:

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Prove that the product of 4 consecutive positive integers is never a perfect square.

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Remember to read the http://www.mathhelpboards.com/showthread.php?772-Problem-of-the-Week-%28POTW%29-Procedure-and-Guidelines to find out how to http://www.mathhelpboards.com/forms.php?do=form&fid=2!
 
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Congratulations to the following members for their correct solution::)

1. kaliprasad
2. lfdahl

Here's the proposed solution:
Let $n,\,n+1,\,n+2$, and $n+3$ be the four consecutive positive integers.

Observe that

$n(n+1)(n+2)(n+3)=(n^2+3n)(n^2+3n+2)=k(k+2)$, where $k=n^2+3n$, but $k^2+2k$ is never a square since

$k^2<k^2+2k<(k+1)^2$

Therefore we can conclude by now that the product of 4 consecutive positive integers is never a perfect square.
 

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