Proving the Square of an Integral Using a Theorem

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Homework Help Overview

The discussion revolves around proving the equality of the square of an integral with a double integral involving a function f. The subject area pertains to integral calculus and the application of theorems related to double integrals.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the meaning of the double integral \(\int_a^b f(x) f(y) dx dy\) and question whether a theorem is necessary for the proof. Some suggest that understanding the right-hand side is key, while others emphasize the importance of Fubini's theorem in handling double integrals.

Discussion Status

The discussion is active, with participants sharing insights about Fubini's theorem and its relevance to the problem. There is a mix of interpretations regarding the need for a theorem, and some participants are seeking clarification on how to relate the left-hand side to a double integral.

Contextual Notes

There is some confusion regarding the notation and the setup of the integrals, particularly in distinguishing between single and double integrals. Participants are also navigating the implications of treating variables as constants in the context of iterated integrals.

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Homework Statement


What theorem do you use to prove that

[tex]\left(\int_a^b f(x) dx \right)^2 = \int_a^b f(x) f(y) dx dy[/tex]

?

Homework Equations


The Attempt at a Solution

 
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What exactly does [itex]\int_a^b f(x) f(y) dx dy[/itex] mean?
 
I don't think you need to use any theorem. Just look at what the RHS means, as morphism said.
 
You most certainly need a theorem here!
It is called Fubini's theorem.

The essence is that double integrals CAN be handled as iterated integrals, simplifying our job immensely.
 
morphism said:
What exactly does [itex]\int_a^b f(x) f(y) dx dy[/itex] mean?

Sorry I meant [tex]\int_a^b \int_a^b f(x) f(y) dx dy[/tex].

arildno said:
You most certainly need a theorem here!
It is called Fubini's theorem.

The essence is that double integrals CAN be handled as iterated integrals, simplifying our job immensely.

But how do you prove the LHS is a double integral OR an iterated integral?
 
Fubini's theorem states that the double integral
[itex]\int \int F(x,y) dx dy[/itex]
is the same as the repeated integral
[tex]\int \left(\int F(x,y)dy\right) dx[/itex]<br /> where the "inner integral" is taken treating x as a constant.<br /> <br /> The crucial point here is that your F(x,y)= f(x)f(y) is a product of two functions, one a function of x only, the other a function of y only.<br /> [tex]\int\left(\int f(x)f(y)dy\right)dx= \int f(x)\left(\int f(y)dy\right) dx[/tex][/tex]
 

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