Proving the Wielandt-Hoffman inequality

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SUMMARY

The discussion focuses on proving the Wielandt-Hoffman inequality for symmetric matrices A and A+E. It establishes two key results: (a) the squared differences of eigenvalues are bounded by the Frobenius norm of the perturbation matrix E, and (b) the absolute difference of the k-th eigenvalue is bounded by the 2-norm of E. The Courant-Fischer Minimax theorem is referenced as a critical tool for deriving these inequalities.

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  • Understanding of symmetric matrices and their properties
  • Familiarity with eigenvalues and eigenvectors
  • Knowledge of Frobenius norm and 2-norm
  • Comprehension of the Courant-Fischer Minimax theorem
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  • Study the application of the Courant-Fischer Minimax theorem in matrix perturbation theory
  • Explore the properties and applications of the Frobenius norm in linear algebra
  • Investigate the implications of eigenvalue perturbation bounds in numerical analysis
  • Learn about the Wielandt-Hoffman inequality and its significance in matrix theory
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Homework Statement


For a symmetric matrix A, use the notation \lambda_{k}\left(A\right) to denote the k^{th} largest eigenvalue, thus

\lambda_{n}\left(A\righ)<=...<=\lambda_{2}\left(A\right)<=\lambda_{1}\left(A\right)

Now suppose A and A+E are nxn symmetric matrices, prove the following results:

(a) \sum(\lambda_{i}\left(A+E\right)-\lambda_{i}\left(A\right))^{2}<=norm(E)_{F}^{2} (Frobenius norm).

(b)|\lambda_{k}\left(A+E\right)-\lambda_{k}\left(A\right)|<=norm(E)_{2} (2-norm) for k=1,...,n.


Homework Equations


Courant-Fischer Minimax theorem
\lambda_{k}\left(A\right)+\lambda_{k}\left(E\right)<=\lambda_{k}\left(A+E\right)<=\lambda_{k}\left(A\right)+\lambda_{1}\left(E\right)



The Attempt at a Solution


I am not really sure how to use the Courant-Fischer Minimax theorem to establish that relationship in 2. If I had some pointers I am sure I could produce something.
 
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