Proving Union of Sets: A Mathematical Induction Approach

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SUMMARY

This discussion focuses on proving the equality of two set expressions using mathematical induction. The statement to prove is that for sets A_1, A_2, …, A_n and B, the equation (A_1 – B) U (A_2 – B) U … U (A_n – B) = (A_1 U A_2 U … U A_n) – B holds true. The proof involves three steps: establishing the base case for n=1, assuming the statement is true for n=k, and proving it for n=k+1. The discussion emphasizes the importance of demonstrating that each side of the equation is a subset of the other to establish equality.

PREREQUISITES
  • Understanding of set theory concepts, specifically set operations (union and difference).
  • Familiarity with mathematical induction principles and techniques.
  • Knowledge of subset definitions and proofs.
  • Basic algebraic manipulation of set expressions.
NEXT STEPS
  • Study the principles of mathematical induction in detail.
  • Learn about set theory operations, focusing on union and set difference.
  • Practice proving set equalities through subset demonstrations.
  • Explore examples of mathematical induction applied to various mathematical statements.
USEFUL FOR

This discussion is beneficial for students studying discrete mathematics, particularly those learning about set theory and mathematical induction. It is also useful for educators seeking to explain these concepts effectively.

Goldenwind
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Homework Statement


Prove that if A_1,A_2,…,A_n and B are sets, then
(A_1 – B) U (A_2 – B) U … U (A_n – B) = (A_1 U A_2 U … U A_n) – B.

Homework Equations


The chapter this is in is based on mathematical induction, which might be a big hint.

Mathematical induction:
Step 1: Prove for the base-case (n = 1)
Step 2: Prove for the general case (n = k)
Step 3: Prove for the advancing case (n = k+1)

The Attempt at a Solution


I haven't a clue how to prove this in mathematical terms, but I know how to give an analogy to demonstrate that I understand the scenario.

Imagine people are lined up to enter a building. As they enter the building (As you introduce each union), each person is carrying a bag (A1, A2, A3, etc). When they enter the building, their bags are searched, and anything on the "No-entry" list (Set B) is removed (An airport example would be removing sharp objects, etc).

(Left side:) If you let people in, and remove their "No-entry" objects upon entry...

(equals)...the result will be the same as...

(Right side:) ...if you let them all in, and then removed their "No-entry" objects inside.

This demonstrates that I understand the problem, and through just gosh darned common freakin' sense, I know that this is a true fact.

However, I predict only getting part marks for not using mathematical induction, OR for not using mathematical terms.
My car has stalled; can anyone gimme a push? ;)
 
Last edited:
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Goldenwind said:
My car has stalled; can anyone gimme a push? ;)

Hi Goldenwind!

No, I'll steer, and you push! :wink:

Hint: Rewrite (A_1 U A_2 U … U A_n) – B as C_n - B.

Does that help? :smile:

[size=-2][noparse](… and you have to type ":wink:"!)[/noparse][/size]​
 
If n= 1, this just says "A1- B= A1- B" which is obviously true.

Now suppose that the statement is true for n= k, so that "(A1- B)U (A2-B)U ...U (Ak- B)= (A1-B)U(A2-B)U...UAk)- B.

Let Ak+1 be any set. You need to prove that (A1U (A2U ...U(Ak- B)U(Ak+1- B)= (A1UA2U...UAkUAk+1)- B.

The standard way of proving that two sets are equal is to prove each is a "subset" of the other. And the standard way to prove "X is a subset of Y" is to say "if x is in X" and then show "x is in Y".

If x is in (A1U (A2U ...U(Ak- B)U(Ak+1- B) then it is in at least one of the sets Ai- B for i from 1 to k+ 1, which means it is in Ai but not in B. Do you see how that implies it is in (A1UA2U...UAkUAk+1)- B?

Now do it the other way around. If x is in (A1UA2U...UAkUAk+1)- B, then it is in that union, but, again, not in B. What do you have to show to prove x is in (A1U (A2U ...U(Ak- B)U(Ak+1- B)?
 

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