Proving Uniqueness in Subspace Addition

Click For Summary
SUMMARY

The discussion focuses on proving the uniqueness of vector addition in subspaces S and T. It establishes that if A + B = A' + B' for vectors A, A' in S and B, B' in T, then A - A' and B - B' must both equal the zero vector, confirming that the sum A + B can only be represented uniquely. This conclusion is derived from the properties of vector subspaces, specifically their additive structure. The proof demonstrates that the only vector common to both subspaces is the zero vector, ensuring uniqueness in representation.

PREREQUISITES
  • Understanding of vector spaces and subspaces
  • Familiarity with vector addition and properties of zero vectors
  • Knowledge of linear independence and dependence
  • Basic concepts of linear algebra, particularly in the context of vector operations
NEXT STEPS
  • Study the properties of vector spaces and subspaces in linear algebra
  • Learn about the concept of linear combinations and their implications
  • Explore the role of the zero vector in vector spaces
  • Investigate examples of unique representations in higher-dimensional vector spaces
USEFUL FOR

Students of linear algebra, mathematicians, and anyone studying vector spaces and their properties will benefit from this discussion.

TranscendArcu
Messages
277
Reaction score
0

Homework Statement


http://img854.imageshack.us/img854/5683/screenshot20120116at401.png

The Attempt at a Solution

So we have that A + B is a vector in S + T, where A is an element of S and B is an element of T. Suppose there is another vector A' + B' also in S + T, where A' is an element of S and B' is an element of T. Let A + B = A' + B' to suppose that the sum cannot be written uniquely. This implies that A + B - A' - B' = 0. This implies that A - A' + B - B' = 0. This implies that B - B' is the additive inverse of A - A', but this is only true if A - A' and B - B' are both in the same subspace. Therefore, A - A',B - B' must both be elements of S,T. But, by definition, the only element in both S,T is 0. Therefore, the only vector that can be written as A + B = A' + B' is the zero vector, which is necessarily unique as a consequence of the properties of subspaces. Therefore, all vectors can be written as unique combinations of A + B.

Am I doing this right? I haven't done the second part yet.
 
Last edited by a moderator:
Physics news on Phys.org
That's ok.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
7K
Replies
8
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
9
Views
2K