Proving Uniqueness of x in x^2 = xsinx + cosx Using Mean Value Theorem"

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SUMMARY

The discussion centers on proving the uniqueness of solutions for the equation x^2 = xsinx + cosx using the Mean Value Theorem. The user has established that there are solutions in the intervals [1, 1.5] and [-1.5, -1] but seeks to demonstrate that these solutions are unique. The function f(x) = x^2 - xsinx - cosx is evaluated, revealing that f(1) < 0 and f(1.5) > 0, confirming the existence of at least one root in the specified interval. The user suggests that a geometric argument may support their findings, but they are encouraged to apply the Mean Value Theorem for a more rigorous proof.

PREREQUISITES
  • Understanding of the Mean Value Theorem
  • Familiarity with the Intermediate Value Theorem
  • Basic knowledge of trigonometric functions and their properties
  • Ability to analyze and evaluate polynomial functions
NEXT STEPS
  • Study the application of the Mean Value Theorem in proving uniqueness of solutions
  • Explore the properties of even functions and their implications on symmetry
  • Investigate numerical methods for finding roots of equations
  • Review geometric interpretations of function behavior and their relation to calculus
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Students studying calculus, particularly those interested in the application of the Mean Value Theorem, as well as educators and tutors seeking to enhance their understanding of function analysis and uniqueness proofs.

cochemuacos
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Mean value theroem??

Homework Statement



Show that [tex]x^2 = xsinx + cosx[/tex] is true only for two values of [tex]x \in {R}[/tex]

Homework Equations



Intermediate value theorem
Mean value theorem (?)

The Attempt at a Solution



I already know how to prove that there is al least one [tex]x \in [1,1.5][/tex] and another [tex]x \in [-1.5,-1][/tex] where the equation holds. The thing is that I'm not completely sure how to pove that they are unique, I have a geometric argument buy i feel it can be done using the mean value theorem.

Just for you to know, what i did to find out where the x's are, i took [tex]f(x) = x^2-xsinx-cosx[/tex] and gave values to the function it turns out that [tex]f(1) < 0[/tex] and [tex]f(1.5) > 0[/tex] so there must be at leat one [tex]x \in [1,1.5][/tex] where [tex]f(x) = 0[/tex] But that's it, I ran out of ideas although i feel I'm really close.

Any ideas or advices will be appreiciated
 
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Have you noticed that the function is even? :smile:
 

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