Pulley question / rotational kinematics

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Homework Help Overview

The problem involves a pulley system with two blocks, where block A is on a tabletop and block B is hanging. The setup includes parameters such as the radius of the pulley, its moment of inertia, and the coefficient of kinetic friction. The objective is to determine the speed of block B as it descends, using energy methods while considering the effects of friction.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of conservation of energy principles, questioning the initial conditions and the roles of different masses in the energy equation. There is exploration of the relationship between the velocities of blocks A and B, and the implications of friction on the system's energy balance.

Discussion Status

The discussion is active, with participants providing insights and corrections regarding the energy equation. Some guidance has been offered regarding the dimensional consistency of terms in the equation, and there is an ongoing examination of the assumptions made about the velocities of the blocks.

Contextual Notes

Participants are navigating through the implications of the pulley system's constraints, including the non-stretching rope and the effects of friction on the energy calculations. There are indications of confusion regarding initial conditions and the treatment of various terms in the energy equation.

alco19357
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Homework Statement


attachment.php?attachmentid=38716&stc=1&d=1315677877.jpg


Summary:
The pulley in the figure has radius (R) and a moment of inertia (I). The rope does not slip over the pulley, and the pulley spins on a frictionless axle. The coefficient of kinetic friction between block A and the tabletop is [itex]\mu[/itex]k. The system is released from rest, and block B descends. Block A has mass (ma) and block B has mass (mb).

Question:
Use energy methods to calculate the speed of block B as a function of the distance (d) that it has descended.
Express your answer in terms of the variables ma, mb, R, I, [itex]\mu[/itex]k, d and appropriate constants


Homework Equations


Conservation of Energy:

PEi + KEi = PEf + KEf + frictional work


The Attempt at a Solution



(magd) + (mbgd) = maVa2/2 + mbVb2/2 + I[itex]\omega[/itex]2/2 + [itex]\mu[/itex]kmg

0 + (mbgd) = 0 + mbVb2/2 + I[itex]\omega[/itex]2/2 + [itex]\mu[/itex]kmg


Is this right?
 

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alco19357 said:
0 + (mbgd) = 0 + mbVb2/2 + I[itex]\omega[/itex]2/2 + [itex]\mu[/itex]kmg


Is this right?
Two questions
1. Why is this zero?
2. Which mass is this?
 
1. I don't know. I thought maybe that the velocity of a is non existent, but wouldn't the velocity of a equal the velocity of b?

2. I would say since the frictional work done is between the surface and object a, that mass should be the mass of block a.

Thank you for your help
 
alco19357 said:
1. I don't know. I thought maybe that the velocity of a is non existent, but wouldn't the velocity of a equal the velocity of b?
If the velocity of a were zero and the velocity of b were not, the distance between the two blocks would increase in which case the rope connecting them would stretch. This is not what happens. If the rope is not to stretch (or shrink), the two blocks must always have the same instantaneous velocity and acceleration.

alco19357 said:
2. I would say since the frictional work done is between the surface and object a, that mass should be the mass of block a.
Correct. Now put it together.
 
Thank you for the help. I applied what you said and got the following answer:

attachment.php?attachmentid=38739&stc=1&d=1315749141.png


What have I done wrong?

Thanks
 

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Look at your numerator under the radical. You are adding two terms that are dimensionally inconsistent. What are the dimensions of each term?
 
I think what you're saying is that I have:

[(m^3) / (s^2)] - [(m^2) / (s^2)]

So am I missing the d variable? So should it be:
(m_B * g * d) - (u_k * m_A * g * d)
 
Yes, that's what the numerator under the radical ought to be.
 
Thank you so much! :smile:

That's the right answer!
 

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