Pulley question / rotational kinematics

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alco19357
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Homework Statement


attachment.php?attachmentid=38716&stc=1&d=1315677877.jpg


Summary:
The pulley in the figure has radius (R) and a moment of inertia (I). The rope does not slip over the pulley, and the pulley spins on a frictionless axle. The coefficient of kinetic friction between block A and the tabletop is [itex]\mu[/itex]k. The system is released from rest, and block B descends. Block A has mass (ma) and block B has mass (mb).

Question:
Use energy methods to calculate the speed of block B as a function of the distance (d) that it has descended.
Express your answer in terms of the variables ma, mb, R, I, [itex]\mu[/itex]k, d and appropriate constants


Homework Equations


Conservation of Energy:

PEi + KEi = PEf + KEf + frictional work


The Attempt at a Solution



(magd) + (mbgd) = maVa2/2 + mbVb2/2 + I[itex]\omega[/itex]2/2 + [itex]\mu[/itex]kmg

0 + (mbgd) = 0 + mbVb2/2 + I[itex]\omega[/itex]2/2 + [itex]\mu[/itex]kmg


Is this right?
 

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1. I don't know. I thought maybe that the velocity of a is non existent, but wouldn't the velocity of a equal the velocity of b?

2. I would say since the frictional work done is between the surface and object a, that mass should be the mass of block a.

Thank you for your help
 
alco19357 said:
1. I don't know. I thought maybe that the velocity of a is non existent, but wouldn't the velocity of a equal the velocity of b?
If the velocity of a were zero and the velocity of b were not, the distance between the two blocks would increase in which case the rope connecting them would stretch. This is not what happens. If the rope is not to stretch (or shrink), the two blocks must always have the same instantaneous velocity and acceleration.

alco19357 said:
2. I would say since the frictional work done is between the surface and object a, that mass should be the mass of block a.
Correct. Now put it together.
 
Thank you for the help. I applied what you said and got the following answer:

attachment.php?attachmentid=38739&stc=1&d=1315749141.png


What have I done wrong?

Thanks
 

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I think what you're saying is that I have:

[(m^3) / (s^2)] - [(m^2) / (s^2)]

So am I missing the d variable? So should it be:
(m_B * g * d) - (u_k * m_A * g * d)
 
Thank you so much! :smile:

That's the right answer!