Pulley system to balance the weight of a person

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Homework Help Overview

This discussion revolves around a pulley system designed to balance the weight of a person, focusing on the tensions in the ropes and the forces acting on the pulleys. The subject area includes mechanics and equilibrium in physics.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationships between the tensions in the ropes, questioning the derivation of specific equations and the assumptions made regarding the system's equilibrium. There are attempts to clarify the logic behind the equations and to simplify the reasoning.

Discussion Status

The discussion is active, with participants providing feedback on each other's reasoning and equations. Some guidance has been offered regarding the use of free body diagrams to clarify the forces involved. There is ongoing exploration of the correct relationships between the tensions and the weights involved.

Contextual Notes

Participants note the importance of considering the mass of the upper pulley and the need for clarity in presenting equations. There is an emphasis on ensuring that all forces, including weights, are accounted for in the analysis.

lorenz0
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Homework Statement
If the mass of the man to be saved is ##m##, the mass of the smaller pulley ##m_p## and the mass of the bigger pulley ##M_p##, find: ##T_1, T_2, T_3, T_4, T_5, F.##
Relevant Equations
##\vec{F}=m\vec{a}##
Since we are dealing with an ideal rope, we have that ##T_1=T_2=T_3=F and T_2+T_3=2F=(m+m_p)g\Leftrightarrow F=\frac{m+m_p}{2}g.##
##T_4=3F+(m+m_p+M_p)g=\frac{3}{2}(m+m_p)g+(m+m_p+M_p)g=(\frac{5}{2}m+\frac{5}{2}m_p+M_p)g## and ##T_5=mg-2F.##

Is this correct? If not, I woould appreciate a brief explanation on how to deal with these ideal-pulley ideal-rope systems since they seem quite counterintuitive to me.
 

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I agree that ##T_1 = T_2 = T_3## and that we can call this ##F##. As you say, the pulleys are ideal so all three tensions will match.

I agree that ##T_2 + T_3 = 2F##. Since those two tensions support the man plus the smaller pulley, it follows that ##2F = (m+m_p)g##. So yes, we can conclude that ##F=\frac{m+m_p}{2}g##

You will have to persuade me that ##T_4 = 3F + (m + m_p + M_p)g##. How did you arrive at that? I think you are double dipping there.
 
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@lorenz0, in addition to what @jbriggs444 has said, can I add this...

Presumably the system is in equilibrium (acceleration = 0).

Your equations/logic could be clearer if not joined together into a single line/paragraph.

The facts that ##T_1 = T_2 = T_3## and ##T_2+T_3=2F## lead to ##T_1 = F##. Can you see a simpler way to get this relationship directly?

All parts of the system are in equilibrium. You can draw a free body diagram for any part of the system. If you draw (or just imagine) a free body diagram for the upper pulley alone, it should help you.
 
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Steve4Physics said:
@lorenz0, in addition to what @jbriggs444 has said, can I add this...

Presumably the system is in equilibrium (acceleration = 0).

Your equations/logic could be clearer if not joined together into a single line/paragraph.

The facts that ##T_1 = T_2 = T_3## and ##T_2+T_3=2F## lead to ##T_1 = F##. Can you see a simpler way to get this relationship directly?

All parts of the system are in equilibrium. You can draw a free body diagram for any part of the system. If you draw (or just imagine) a free body diagram for the upper pulley alone, it should help you.
Drawing the free body diagram for the upper pulley alone, it seems that ##T_4=3F+M_Pg.## Is this correct?
 
Last edited:
lorenz0 said:
Drawing the free body diagram for the upper pulley alone, it seems that ##T_4=3F.## Is this correct?
No. You missed something this time.
 
jbriggs444 said:
No. You missed something this time.
The mass of the upper pulley, I guess.
 
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lorenz0 said:
Drawing the free body diagram for the upper pulley alone, it seems that ##T_4=3F.## Is this correct?
Pulley.jpg
 
lorenz0 said:
The mass of the upper pulley, I guess.
You mean the weight of the upper pulley. (Hopefully it's not a 'guess', as a free body diagram must include the body's weight.) Your Post #4 edited equation is now correct.

BTW, it's best to not significantly edit a post once someone has replied to it. Better to write a new Post making clear any changes you want. That can avoid confusion and messages at cross-purposes.
 
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