Pulley/Torque problem where pulley has mass

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Homework Help Overview

The problem involves two objects connected by a light string over a pulley with mass and moment of inertia. The objects are released from rest, and the task is to find their translational speeds and the angular speed of the pulley using conservation of energy principles.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of free body diagrams and the equations of motion for the masses. There is an attempt to express acceleration in terms of variables and to relate it to the translational speeds using energy conservation.

Discussion Status

Some participants have provided guidance on the equations to consider, while others are exploring the relationship between potential energy loss and kinetic energy gain. There is a focus on clarifying the steps needed to express the solution in variable form.

Contextual Notes

Participants are navigating the requirement to solve the problem without numerical values, which has led to questions about the correct approach and the use of specific formulas.

tron_2.0
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hi, I am new to the forum =] my names suraj and I am an engineering/journalism student in my first year. this forum looked pretty informative so i figured id sign up. anyways id really appreciate it if someone could help me out on this problem.

Homework Statement



Consider two objects with connected by a light string that passes over a pulley having a moment of inertia of about its axis of rotation as shown in the figure below. The string does not slip on the pulley or stretch. The pulley turns without friction. The two objects are released from rest separated by a vertical distance .

(a) Use the principle of conservation of energy to find the translational speeds of the objects as they pass each other.
(b) Find the angular speed of the pulley at this time.


Homework Equations


well not given in the problem but i believe you have to apply:
-Free Body Diagrams (of both masses)
-Torque=Fd
-Kinematics

The Attempt at a Solution



okay well i tried to solve it in the variable form that the question is asking for, and i was unable to do so. however i tried to plug in some numbers (give each mass a numerical mass, give the pulley a random mass, etc) and i believe i solved the problem. I am just confused as to how i should solve it in the form using variables?


this is what i got when i made up values for the pulley's mass, the pulley's radius, the mass of the weight on the left, and the mass of the weight on the right:

http://i21.photobucket.com/albums/b277/riceboy89/solution1.jpg

however it is asking me the answer in terms of variables, and I am having a hard time trying to find my acceleration in terms of variables so i can use the equation i ended up in the above solution (i figured that if i can solve for a in terms of variables, can't i just plug it into v=sqrt(2a*deltaY)?)

http://i21.photobucket.com/albums/b277/riceboy89/solution2.jpg

thanks for the guidance
 
Last edited by a moderator:
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Hi Suraj!

In http://i21.photobucket.com/albums/b277/riceboy89/solution2.jpg" pic, as

[tex]m_1>m_2[/tex] the equations should be

[tex]m_1g-T_1=m_1a[/tex]

and

[tex] T_2-m_2g=m_2a[/tex]

The [tex]\tau=I\alpha[/tex] equation looks good to me.
 
Last edited by a moderator:
You will have a loss in PE balanced by a gain in KE and work done.

What is it that loses PE, and by how much ?

What are the gains in KE and by how much ?

What work is done and how much ?
 
google_spider:

am i on the right track in finding the acceleration first, in terms of variables, and then plugging it into the equation (sqrt(2a*deltaY))?
 
tron_2.0 said:
am i on the right track in finding the acceleration first, in terms of variables, and then plugging it into the equation (sqrt(2a*deltaY))?

What is [tex]a_y=\sqrt{2a\delta y}[/tex] ?? I have never come across this formula. As Phisixguru pointed out, you have to use energy conservation. Both the blocks will be at a height of 4H when they pass each other.
 
Last edited:

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