Pulleys: One mass hanging between two other masses

  • Thread starter Thread starter geralt
  • Start date Start date
  • Tags Tags
    Mass Pulleys
Click For Summary
SUMMARY

The discussion focuses on a physics problem involving three masses connected by a continuous pulley system, where one mass hangs between two others. The key equations derived include the relationship between the accelerations of the masses, specifically that the acceleration of the hanging mass (m2) can be expressed as a = m2g/(total mass). Participants emphasize using Newton's second law (F = ma) for each mass to derive the tension in the string and the accelerations of the system. The solution requires eliminating tension (T) to find the accelerations of all three masses.

PREREQUISITES
  • Understanding of Newton's second law (F = ma)
  • Basic knowledge of pulley systems and their mechanics
  • Familiarity with mass and gravitational force concepts
  • Ability to set up and solve systems of equations
NEXT STEPS
  • Study the dynamics of pulley systems in physics
  • Learn how to derive equations of motion for multiple connected masses
  • Explore tension in strings and its role in mechanical systems
  • Practice solving problems involving multiple masses and accelerations
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of pulley systems and acceleration calculations.

geralt
Messages
3
Reaction score
0

Homework Statement


Explanation: There are three masses in this problem. Two masses are sitting on two opposite surfaces. These surfaces have a space in between them, where a third mass is hanging down. These masses are connected by a continuous pulley system.

μ = 0.

The question asks us to find the acceleration of the hanging block, and the tension in the string. We are given the following hint: You will need to find a relationship between a1 (acceleration), a2, and a3. If m1 moves distance d1, and m3 moves a distance d3, how far does m2 move?

I've already determined that the acceleration of the hanging block is the average of the acceleration of the other two blocks, but I don't know where to go from there. Any help would be greatly appreciated!

The Attempt at a Solution



The only force would be the hanging mass pulling down on the other two blocks via the pulley. So the force would be m2g, m2 being the hanging mass. The mass would be the total masses of the three blocks. Then using f=ma, I get the equation a=m2g/(total mass). I have no idea for tension...

Please help me if you can!
 
Physics news on Phys.org
oy geralt! welcome to pf! :biggrin:
geralt said:
The only force would be the hanging mass pulling down on the other two blocks via the pulley. So the force would be m2g, m2 being the hanging mass. The mass would be the total masses of the three blocks. Then using f=ma, I get the equation a=m2g/(total mass). I have no idea for tension...

call the tension "T" (the string is continuous, and the pulleys are presumably massless and frictionless, so it'll be the same all the way along)

you need to do F = ma three times, once for each mass

that should give you enough equations to eliminate T and find the accelerations!

show us what you get :smile:
 

Similar threads

Replies
25
Views
4K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 22 ·
Replies
22
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 102 ·
4
Replies
102
Views
8K
  • · Replies 15 ·
Replies
15
Views
6K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 30 ·
2
Replies
30
Views
4K