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Purcell's Electricity and Magnetism - question

  1. Feb 23, 2008 #1
    1. The problem statement, all variables and given/known data
    Purcell 3.3: In the field of a point charge over a plane, if you follow a field line that starts at the point charge in a horizontal direction, that is, parallel to the plane, where does it meet the surface of the conductor?

    2. Relevant equations
    The problem 'hint' is "You'll need Gauss' law and a simple integration."

    3. The attempt at a solution
    The electric field on the surface of the conductor at a radius R=[tex]\sqrt{r^{2}+h^{2}}[/tex] (h is the height of the pt charge, r is the x component of the radius on the plane), the Electric field due to the point charge is:
    E=[tex]\frac{-2Qh}{(r^{2}+h^{2})^{3/2}}[/tex]. This is given in the book.
    I have no idea where to start..
  2. jcsd
  3. Feb 23, 2008 #2
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