Pytels Dynamics 12.39: A rocket is launched vertically

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SUMMARY

The discussion focuses on calculating the altitude of a 2000-kg rocket launched vertically with a constant propulsive force of 60 kN for the first 20 seconds. Participants confirm the application of Newton's second law, specifically ΣFy=ma, to derive the equations of motion. The integration of acceleration to find velocity and displacement is validated as the correct approach to solve the problem. The consensus is that the methodology applied is sound and leads to the desired outcome.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Basic principles of kinematics
  • Knowledge of forces and weight calculations
  • Integration techniques for motion equations
NEXT STEPS
  • Study the application of Newton's laws in vertical motion scenarios
  • Learn about kinematic equations for uniformly accelerated motion
  • Explore the effects of gravitational acceleration on projectile motion
  • Investigate the integration of acceleration to derive velocity and displacement
USEFUL FOR

Students in physics, aerospace engineering enthusiasts, and anyone interested in the dynamics of rocket launches and motion analysis.

Alexanddros81
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Homework Statement


A 2000-kg is launched vertically from the surface of the earth. The engine shuts off after providing a constant propulsive force of 60 kN for the first 20 seconds. Neglect the reduction in the mass of the rocket due to the burning of the fuel and the variation of the gravitational acceleration with altitude. Calculate the altitude of the rocket at the end of the powered portion of the flight.

Homework Equations

The Attempt at a Solution


I have tried applying Newton's second law ΣFy=ma => F-W=ma (1)
Then I found right hand a of eq (1) and done the integration to find v and x.

Is this the right way to go?
 
Physics news on Phys.org
Sounds like a good plan.
 
Pytel_Dynamics040.jpg
Is this correct?
 
Alexanddros81 said:
Is this correct?
Yes. Nice work!
 

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