Q&A: How Does Work & Energy Relate to Solids, Liquids & Gases?

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Homework Help Overview

The discussion revolves around the relationship between work and energy in solids, liquids, and gases, particularly in the context of how these principles apply to different states of matter and their behavior under various conditions.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the application of work and energy principles across different states of matter, questioning how these concepts extend beyond gases to solids and liquids. There are attempts to clarify misunderstandings regarding the conditions under which work is done on or by substances.

Discussion Status

The discussion includes various perspectives on the application of work and energy principles. Some participants provide clarifications and examples to address misconceptions, while others express uncertainty about the completeness of their responses. Input from knowledgeable members is acknowledged as helpful.

Contextual Notes

There is a noted lack of consensus on the general applicability of work and energy principles to all states of matter, with some participants questioning the assumptions underlying the original statements made about these concepts.

Sarah0001
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Homework Statement
"If the volume of the substance does not change, no work is done on or by the substance"
Relevant Equations
ΔU = W+ Q
work=−PΔV
I can understand how this applies to gases as in that scenario work done = pressure * change in volume and if change in volume is zero then W=0
so change in internal energy = Q. But I do not understand how this applies generally to all types of substances, say solid, liquid and gas.
 
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It applies simply to solids, liquids and gases that e.g. in a container or otherwise fixed position where their volume may change, in the presence of an external atmosphere.
It does not apply to a mechanical arm connected to a motor that is able to do work on an object to set it in motion.
Perhaps others can help to answer to this question, because I don't know that I have answered it satisfactorily. @Chestermiller might you have an input here?
 
Sarah0001 said:
I can understand how this applies to gases as in that scenario work done = pressure * change in volume and if change in volume is zero then W=0
so change in internal energy = Q. But I do not understand how this applies generally to all types of substances, say solid, liquid and gas.
You don't understand the statement because it is obviously incorrect. Any loading that involves the deformation of a solid, liquid, or gas automatically involves doing work on or by the substance. Examples of this are stirring, shearing between parallel plates, forcing through a pipe, etc., ad infinitum. It does not only apply to volume changes. In addition to this, even without deformation, the substance can still experience a change in kinetic energy and/or kinetic energy, which is the result of doing work on or by the substance.
 
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Chestermiller said:
You don't understand the statement because it is obviously incorrect. Any loading that involves the deformation of a solid, liquid, or gas automatically involves doing work on or by the substance. Examples of this are stirring, shearing between parallel plates, forcing through a pipe, etc., ad infinitum. It does not only apply to volume changes. In addition to this, even without deformation, the substance can still experience a change in kinetic energy and/or kinetic energy, which is the result of doing work on or by the substance.
Thank you very much @Chestermiller I didn't know the complete answer, but that's exactly the kind of input I was looking for. Many thanks! :smile::smile::smile:
 

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