(adsbygoogle = window.adsbygoogle || []).push({}); [SOLVED] Q=mcT heat problem, were did i go wrong?

1. The problem statement, all variables and given/known data

If a 45g sample of aluminum at 22 degrees C is given 6.0 x 10^3 J of heat, what will its final temperature be?

2. Relevant equations

[tex]Q = mc \Delta T[/tex]

3. The attempt at a solution

i found in my textbook that aluminum has a specific heat capacity of 900

so c = 900.

[tex]Q = mc \Delta T [/tex]

[tex]Q = mc( T' - T ) [/tex]

[tex]T' - T = \frac{Q}{mc} [/tex]

[tex]T' = \frac{Q + T}{mc}[/tex]

[tex]T' = \frac{(6.0 x 10^3 J) + 22\deg}{(0.045kg)(900)} [/tex]

**Physics Forums - The Fusion of Science and Community**

# Q=mcT heat problem, were did i go wrong?

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

- Similar discussions for: Q=mcT heat problem, were did i go wrong?

Loading...

**Physics Forums - The Fusion of Science and Community**