[SOLVED] Q=mcT heat problem, were did i go wrong? 1. The problem statement, all variables and given/known data If a 45g sample of aluminum at 22 degrees C is given 6.0 x 10^3 J of heat, what will its final temperature be? 2. Relevant equations [tex]Q = mc \Delta T[/tex] 3. The attempt at a solution i found in my textbook that aluminum has a specific heat capacity of 900 so c = 900. [tex]Q = mc \Delta T [/tex] [tex]Q = mc( T' - T ) [/tex] [tex]T' - T = \frac{Q}{mc} [/tex] [tex]T' = \frac{Q + T}{mc}[/tex] [tex]T' = \frac{(6.0 x 10^3 J) + 22\deg}{(0.045kg)(900)} [/tex]
Re: [SOLVED] Q=mcT heat problem, were did i go wrong? kurdt , what would the worked out solution look like for the last step?