- #1

- 2,518

- 456

The following is summary of what I think I have learned so far from the previous discussion cited above about Hawking Radiation.

1. Hawking Radiation (HR) involves multiple events, each involving the creation of a particle pair (PP), a particle and its anti-particle, outside but close to the event horizon (EH) of a black hole (BH). For the purpose of this discussion it is assumed that the BH is non-rotating, and it and its gravitational field (GF) are spherically symmetrical.

2. The EH of the black hole is a sphere of radius

2. The EH of the black hole is a sphere of radius

R

_{c}= GM/c^{2}.a) M is the mass equivalent of all the mass and energy inside the EH. This mass-energy is assumed to include a point singularity at the center of the black hole, and this point singularity contains all of the mass-energy M

b) The amount M_i of M corresponding to the GF energy inside the BH is functionally related to the amount M_s of M at the point singularity.

c) M_s + M_i = M

d) M_s is functionally related to the total GF energy both inside and outside the EH.

__except__the energy of the GF which occupies the volume within EH.b) The amount M_i of M corresponding to the GF energy inside the BH is functionally related to the amount M_s of M at the point singularity.

c) M_s + M_i = M

d) M_s is functionally related to the total GF energy both inside and outside the EH.

3. The PP creation event takes place over a very brief period of time in which several changes in M and the GF occur. For each such PP creation:

a) Some of the energy in the GF outside, but near, the EH is converted into the PP.

b) There are

d) The reduction of energy inside the EH depends on which of the three above scenarios is involved.

b) There are

__logically__three possible scenarios regarding this PP.(i) The most likely is that one of the pair escapes entirely from the BH as it begins its travels towards infinity. The other particle crosses into the volume inside the EH.

(ii) Both of the two particles escape the BH.

(iii) Both of the two particles cross into the volume inside the EH.

c) An amount of mass-energy inside the EH, equal to the GF energy outside of the EH that was converted into the PP, “vanishes”. Most of this mass-energy “moves” outside the EH so that the GF there almost equals what it had been before the PP creation. The net reduction in the GF energy outside the EH is due to the weakening of the GF due the reduction of M inside the event horizon.(ii) Both of the two particles escape the BH.

(iii) Both of the two particles cross into the volume inside the EH.

d) The reduction of energy inside the EH depends on which of the three above scenarios is involved.

(i) The reduction is slightly less than one-half of the total energy used to create the PP, since one of the pair replaces half of the energy that vanished inside the EH.

(ii) The reduction is slightly less than the total energy used to create the PP.

(iii) The reduction is zero since both particles replace the vanished inside energy.

e) The reduction of M includes: (i) a reduction in the mass at the point singularity, and (ii) a reduction in the energy of the GF inside the EH.(ii) The reduction is slightly less than the total energy used to create the PP.

(iii) The reduction is zero since both particles replace the vanished inside energy.

4. When the event has completed, the GF is again spherically symmetrical. The details of what is physically happening during the event that causes the energy to move around to accomplish the changes described above is

__unknown__at the present state of understanding of Quantum Gravity (QG) theory.

My first question is: Have I made any mistakes? That is:

Does the above summary description of the Hawking Radiation phenomenon contradict anything that is known with respect to the current state of knowledge about this phenomenon?

If I have made any mistakes, I would be most grateful if someone will post corrections.Regards,

Buzz