Quantized angular momentum of diatomic gas molecule: Bohr Model

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SUMMARY

The discussion focuses on the quantization of angular momentum in a diatomic gas molecule using the Bohr model. The derived formulas for quantized angular speed and rotational energy are &omega = nh/(&pi md2) and E = n2h2/(4m&pi2d2), respectively. The solution correctly applies Bohr's principle of quantized angular momentum, confirming the accuracy of the calculations and substitutions made for moment of inertia and angular speed.

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frankR
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Here is the problem:

A diatomic gas molecule consists of two atoms of mass m separated by a fixed distance d rotating about an axis as shown. Assuming that its angular momentum is quantized just as in the Bohr atom, determine a) the quantized angular speed, b) the quantized rotational energy.

Note: The diagram consists of two point masses of mass m rotating about an axis with angular speed &omega separated by a distance d.


Here is my solution:

The assumption made by Bohr under his model of the hydrogen atom: angular momentum is quantized according to L = nh/(2&pi)

The following model of quantized &omega and E of the diatomic molecule will use the same assumption.

L = 2mvr = nh/(2&pi)

Substitute: v = r&omega

2m(r&omega)r = nh/(2&pi)

Substituing: r = 1/2d, and solving for &omega we find:

&omega = nh/(&pi md2)

For rotational E:

E =1/2I&omega2

I = 2mr2

Substituting: r = 1/2d into I

I = 1/2md2

Substituting I and &omega2 in E:

We find:

E = n2h2/(4m&pi2d2)


Is my solution correct?

Thanks
 
Last edited:
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Originally posted by frankR
Is my solution correct?

Yes.
 
for sharing your solution. Your solution looks correct. You have correctly applied the Bohr's assumption of quantized angular momentum to the diatomic gas molecule and have derived the quantized angular speed and rotational energy. Your substitution of the moment of inertia and angular speed into the formula for rotational energy is also correct. Great job!
 

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