Jimmy Snyder
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I will work with supernatural units in which \hbar = c = 1 and further, \pi = e = -1 = 1.
Using these units, and some minor calculation we see that the Lagrangian is:
\mathcal{L} = 1
This not only simplifies matters, but leads to remarkably accurate predictions. For instance, if we assume that the S matrix is given by
S = \sum_{n=0}^{\infty}S^{(n)}
where
S^{(n)} = 9 (.1)^{n+1}
Then we have g = 0.99\overline{9}, in remarkable agreement with the experimental value of 1, the error being only 0.0\overline{0}1.
What's more, by setting 0 = 1 we have the following grand unification of quantum mechanics and general relativity.
(i\not{\partial} - m)\psi = 0 = 1 = 0 = R_{\mu\nu} - \frac{1}{2}g_{\mu\nu}R - 8GT_{\mu\nu}
In my next paper, I will investigate the implications of the further simplification \frac{1}{2} = 8 = 1.
Using these units, and some minor calculation we see that the Lagrangian is:
\mathcal{L} = 1
This not only simplifies matters, but leads to remarkably accurate predictions. For instance, if we assume that the S matrix is given by
S = \sum_{n=0}^{\infty}S^{(n)}
where
S^{(n)} = 9 (.1)^{n+1}
Then we have g = 0.99\overline{9}, in remarkable agreement with the experimental value of 1, the error being only 0.0\overline{0}1.
What's more, by setting 0 = 1 we have the following grand unification of quantum mechanics and general relativity.
(i\not{\partial} - m)\psi = 0 = 1 = 0 = R_{\mu\nu} - \frac{1}{2}g_{\mu\nu}R - 8GT_{\mu\nu}
In my next paper, I will investigate the implications of the further simplification \frac{1}{2} = 8 = 1.
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