Undergrad Quasi-Static Processes: Does dQ = 0?

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In quasi-static processes, the relationship dQ = dE + dW holds, but when dW = -dE, it raises the question of whether dQ can equal zero, suggesting no heat exchange. This confusion is particularly relevant in isothermal quasi-static processes, where dQ is not zero. The reference to Reif's Fundamentals of Statistical and Thermal Physics indicates that the work done by the system is defined as dWr = -dEr, implying that dW = -dE is specific to certain conditions. However, it is argued that a system cannot remain in a particular thermodynamic state if its internal energy changes, indicating that the equation may only apply to adiabatic changes. Understanding these distinctions is crucial for accurately interpreting thermodynamic processes.
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We know that dQ = dE + dW for any system. However, in quasi-static processes, dW = -dE. Does this mean that dQ = 0 and no heat (Q) is absorbed or given off? If so, why is that?
 
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manhattan_project said:
We know that dQ = dE + dW for any system.
However, in quasi-static processes, dW = -dE.
Who says that this is the case for a quasi-static process? What about an isothermal quasi-static process, where dQ is not equal to zero?
 
I guess I am confused when dQ = 0.
In Reif's Fundamentals of Statistical and Thermal Physics, in Section 2.9 on quasi-static processes, it states that the work dW done by the system when it remains in a particular state r is defined as dWr = -dEr. I understood this as saying that dW = -dE for quasi-static processes
 
manhattan_project said:
I guess I am confused when dQ = 0.
In Reif's Fundamentals of Statistical and Thermal Physics, in Section 2.9 on quasi-static processes, it states that the work dW done by the system when it remains in a particular state r is defined as dWr = -dEr. I understood this as saying that dW = -dE for quasi-static processes
I don’t have a copy of that book. But, it dorsn’t sound correct to say that a system remains in a particular thermodynamic state if its internal energy changes. The equation you have written is correct only for an adiabatic change.
 
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