Question about a car turning on ice.

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    Car Ice Turning
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When a car turns in a circular motion and encounters a patch of ice, the lack of friction means there is no centripetal force to maintain the turn. The equation μmg=mv²/r illustrates that if the coefficient of friction (μ) is zero, the necessary force for circular motion is absent. Consequently, the car will not continue to turn but will instead move in a straight line. This scenario highlights the critical role of friction in vehicle dynamics during turns. Understanding these principles is essential for safe driving in icy conditions.
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If I was turning in a circular motion in a car, then I hit a patch of ice making the road frictionless. Would my car just go straight? I always have a hard time on these intuitive questions.
 
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Right well if the friction is providing the centripetal force then μmg=mv2/r. Hence if μ=0, then no force is providing the necessary force to carry it in that circular motion, hence yes it would go straight.
 

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