Question about Averages (Kizzy Reem's Question on Facebook)

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SUMMARY

The mean average for 24 students is 78%, resulting in a total score of 1872 marks. When adding a 25th student who scored 67%, the new mean average for all 25 students can be calculated using the formula \(M_{25}=\frac{1}{25}(67+1872)\). This results in a new mean average of 78.4%. The calculations demonstrate how to incorporate additional data into existing averages effectively.

PREREQUISITES
  • Understanding of basic statistics, specifically mean calculations.
  • Familiarity with algebraic expressions and summation notation.
  • Ability to manipulate equations to solve for unknowns.
  • Knowledge of how to apply averages in educational contexts.
NEXT STEPS
  • Study the concept of weighted averages and their applications.
  • Learn about statistical measures beyond the mean, such as median and mode.
  • Explore the implications of outliers on average calculations.
  • Practice solving similar problems involving averages with varying data sets.
USEFUL FOR

Students, educators, and anyone interested in improving their understanding of statistical averages and their calculations.

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Kizzy Reem on Facebook writes:

If the mean average for 24 students is 78% and another student got 67% what is the mean average for the 25 students?
 
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Sudharaka said:
Kizzy Reem on Facebook writes:

If the mean average for 24 students is 78% and another student got 67% what is the mean average for the 25 students?

Hi Kizzy, :)

Let \(x_{i}\) be the marks of the \(i^{th}\) student. Then the mean value of marks for 24 students is,

\[M_{24}=\frac{1}{24}\sum^{24}_{i=1} x_{i}=78\]

\[\Rightarrow \sum^{24}_{i=1} x_{i}=78\times 24~~~~~~~~~~(1)\]

Since the 25th student got 67% marks,

\[M_{25}=\frac{1}{25}\left(67+\sum^{24}_{i=1} x_{i}\right)~~~~~~~~(2)\]

Using (1) and (2) you'll be able to calculate \(M_{25}\). :)
 

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