maeila
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Why is angular momentum conserved for a charge in an electric field?
The discussion revolves around the conservation of angular momentum for a charge in an electric field, exploring the relationship between distance, velocity, and angular momentum in the context of electrostatics and comparing it to gravitational fields. The scope includes theoretical considerations and conceptual clarifications.
Participants express varying levels of understanding and agreement regarding the conservation of angular momentum in electric fields, with some questioning the underlying principles and others providing explanations. No consensus is reached on the relationship between distance, velocity, and angular momentum.
There are unresolved assumptions regarding the initial conditions of the charges and the specific configurations of their motion. The discussion also reflects differing interpretations of how electrostatic forces compare to gravitational forces in terms of angular momentum.
maeila said:Is the velocity of a charge q moving in an electric field generated by Q inversely proportional to the distance r from q to Q? And if so, why?
maeila said:Why is angular momentum conserved for a charge in an electric field?
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Angular momentum (rarely, moment of momentum or rotational) is the rotational equivalent of linear momentum. It is an important quantity in physics because it is intrinsically conserving quantity --the total angular momentum of a system remains constant unless acted on by an external force torque.
https://en.m.wikipedia.org/wiki/Angular_momentumIf You haven't read this article, you could read the pertinent areas of this Wiki Art angular "Conservation of Angular momentum" - - "angular momentum in Orbital mechanics" and '--- "The Law of Areas"maeila said:I don't know, I just can't see how the relation between distance and velocity could justify that.
It made sense in the gravitational field, since when a satellite gets closer it also gets faster. Now, if I have a stationary positive charge and a smaller positive charge in its field, the first charge will accelerate the other to repel it, so with the increasing distance of the second charge there's also an increase in velocity.
Well, if the small charge has no initial velocity it will move along a radial direction and the angular momentum will be zero in any position. The angle alpha in your formula is zero. If it has some non-radial component it will have some angular momentum (in respect to the fixed charge). But the electrostatic force is always radial so there will be no torque applied (again, relative to the origin attached to the fixed charge) and no change in the angular momentum.maeila said:I don't know, I just can't see how the relation between distance and velocity could justify that.
It made sense in the gravitational field, since when a satellite gets closer it also gets faster. Now, if I have a stationary positive charge and a smaller positive charge in its field, the first charge will accelerate the other to repel it, so with the increasing distance of the second charge there's also an increase in velocity.