I know that the convolution of two functions [itex]f(x)[/itex] and [itex]g(x)[/itex] is given by(adsbygoogle = window.adsbygoogle || []).push({});

[tex]

(f * g)(y) = \int_{\mathbb R} f(x)g(y-x) dx.

[/tex]

But what if I'm trying to convolve a function [itex]f(x)[/itex] with a function [itex]g(x + az)[/itex], where [itex]a[/itex] is some constant? Is it just

[tex]

(f*g)(y) = \int_{\mathbb R} f(x)g(y - x + az) dx.

[/tex]

If so, why? I can't seem to find a definition of the convolution that makes this obvious.

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Question about convolutions

**Physics Forums | Science Articles, Homework Help, Discussion**