- #1
Kiko
- 4
- 0
hi all
i have a simple question but answer i don't know how to find :)
lets say we have a electric motor with 1kw at 1500 rpm and that is 4.75 N.m
when the electric motor is connected to worm gearbox n proportion 10:1 then the speed on output point of the gearbox will be 150 RPM. But this mean also that the torque on output point of the gearbox is increased, and that is 9.x kw, let's say 9 kw.
In this case, when we have 9 kw on output point of the gearbox with output speed 150 rpm then: output torque will be 427 N.m
i am correct or?!
If not, then let me know how much torque on N.m i will have on output point of the worm gearbox 10:1 when source el.motor is working on 1 kw with speed 1500 rpm.
im based on calculations on http://wentec.com/unipower/calculators/power_torque.asp
thank you
i have a simple question but answer i don't know how to find :)
lets say we have a electric motor with 1kw at 1500 rpm and that is 4.75 N.m
when the electric motor is connected to worm gearbox n proportion 10:1 then the speed on output point of the gearbox will be 150 RPM. But this mean also that the torque on output point of the gearbox is increased, and that is 9.x kw, let's say 9 kw.
In this case, when we have 9 kw on output point of the gearbox with output speed 150 rpm then: output torque will be 427 N.m
i am correct or?!
If not, then let me know how much torque on N.m i will have on output point of the worm gearbox 10:1 when source el.motor is working on 1 kw with speed 1500 rpm.
im based on calculations on http://wentec.com/unipower/calculators/power_torque.asp
thank you