HI guys, I am trying to build a pulley with a gear box. So I want my pulley, which is operate by a 3V DC motor with max speed of 8300 RPM. I think the size of the output shaft is 3mm Ok, so Can someone help me with how to calculate the original amount of torque I can get out of this motor? and let say the I can connect the shaft to a gearbox with ratio of 300 to 1. Will I be able to pull about 10 lbs with this gear ratio? Assuming I am pulling it over flat surface? Thanks alot.