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Question about height of image and magnification

  1. Aug 3, 2011 #1
    1. The problem statement, all variables and given/known data

    so if the original object is 4.6 cm tall located at x = 0 and it's a concave mirror

    distance from C to the object is 16 cm and Radius of the mirror is 12 cm



    3. The attempt at a solution

    to find the position of x image

    i got 9.6 cm

    then for magnification i got -.6 which is also equal to M = -di/do = Hi /Ho

    so since the object is 4.6 tall the Hi is -2.76cm

    so it's inverted??? and it's real? since it's inside the mirror and the object

    how can Hi be negative what does this mean if the di is negative it's virtural i think so the image is real

    but should the height be in magnitude but what i got from the equation was -2.76cm

    please explain

    thank you
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Aug 3, 2011 #2

    kuruman

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    Homework Helper
    Gold Member

    Positive di means the image is real.
    Negative di means the image is virtual.

    Negative magnification means the image is inverted.
    Positive magnification means the image is erect.
     
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