# Question about height of image and magnification

1. Aug 3, 2011

### yjk91

1. The problem statement, all variables and given/known data

so if the original object is 4.6 cm tall located at x = 0 and it's a concave mirror

distance from C to the object is 16 cm and Radius of the mirror is 12 cm

3. The attempt at a solution

to find the position of x image

i got 9.6 cm

then for magnification i got -.6 which is also equal to M = -di/do = Hi /Ho

so since the object is 4.6 tall the Hi is -2.76cm

so it's inverted??? and it's real? since it's inside the mirror and the object

how can Hi be negative what does this mean if the di is negative it's virtural i think so the image is real

but should the height be in magnitude but what i got from the equation was -2.76cm

thank you
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

2. Aug 3, 2011

### kuruman

Positive di means the image is real.
Negative di means the image is virtual.

Negative magnification means the image is inverted.
Positive magnification means the image is erect.