- #1
yungman
- 5,708
- 240
My understanding of:
[tex]\int_S \nabla X \vec{H} \cdot d\vec{S} = \int_C \vec{H} \cdot d \vec{l} = I [/tex]
Means the current I creates the magnetic field in the form of [itex] \nabla X \vec{H}[/itex] instead of magnetic field creates the current I.
But in the boundary condition, it claims the tangential component of of [itex]\vec{H}[/itex] is continuous if there is no surface current density [itex]\vec{J_S}[/itex] on the boundary. This almost sounds like when an external magnetic field hit a conducting surface, current form on the surface result from the external magnetic field which do not agree with my assertion at the top that it is the current that cause the magnetic field.
I understand that varying magnetic field will cause electric flux in the Maxwell's equation:
[tex] \int_S \nabla X \vec{E} \cdot d \vec{S} = -\frac{\partial \vec{B}}{\partial t} [/tex]
But this is in varying field condition not static condition as in my question.
Can anyone explain to me?
Thanks
Alan
[tex]\int_S \nabla X \vec{H} \cdot d\vec{S} = \int_C \vec{H} \cdot d \vec{l} = I [/tex]
Means the current I creates the magnetic field in the form of [itex] \nabla X \vec{H}[/itex] instead of magnetic field creates the current I.
But in the boundary condition, it claims the tangential component of of [itex]\vec{H}[/itex] is continuous if there is no surface current density [itex]\vec{J_S}[/itex] on the boundary. This almost sounds like when an external magnetic field hit a conducting surface, current form on the surface result from the external magnetic field which do not agree with my assertion at the top that it is the current that cause the magnetic field.
I understand that varying magnetic field will cause electric flux in the Maxwell's equation:
[tex] \int_S \nabla X \vec{E} \cdot d \vec{S} = -\frac{\partial \vec{B}}{\partial t} [/tex]
But this is in varying field condition not static condition as in my question.
Can anyone explain to me?
Thanks
Alan