Question about Momentum and Collisions.

AI Thread Summary
The Impulse-Momentum Theorem relates the change in momentum to the force applied over time. Deriving the time two colliding objects stick together without using the left side of the equation is complex and situation-dependent. Factors influencing this include the nature of the collision, material properties, and initial velocities. Different collision scenarios, such as elastic versus inelastic collisions, will yield varying results. Understanding these dynamics is crucial for accurate calculations in physics.
pghazanfari
Messages
4
Reaction score
0
I am sure many of you are familiar with the Impulse-Momentum Theorem:

\Deltap = F * \Deltat

Is there any way to mathematically derive the time that the two objects would stick together during the collision without using the left side of the equation?
 
Physics news on Phys.org
Depends on the situation.
 
zhermes said:
Depends on the situation.

What would these situations be?
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...
Back
Top