Question about Snell's law and angle of deviation

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SUMMARY

The discussion centers on calculating the angle of deviation in a prism using Snell's law and basic geometry principles. The angle of deviation is derived by subtracting the angle of refraction from the angle of incidence, specifically 70 degrees - 12 degrees, resulting in an angle of deviation of 58 degrees. The user clarifies their confusion regarding the calculation by referencing the exterior angle theorem, which states that the exterior angle of a triangle equals the sum of the two opposite interior angles. This understanding resolves their initial uncertainty.

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John982
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This isn't even a homework question but in my textbook there is an example on how to find the angle of deviation in a prism. I understand how they got all the angles listed in the picture but what I cannot understand is how the angle of deviation can be found from 70 - 12 = 58 degrees (answer in the books example). It's probably a simple issue with my geometry but I'm having trouble figuring it out and the book isn't too clear. Thanks.
http://imageshack.us/photo/my-images/43/33528972.jpg/
 
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John982 said:
In my textbook there is an example on how to find the angle of deviation in a prism. I understand how they got all the angles listed in the picture but what I cannot understand is how the angle of deviation can be found from 70 - 12 = 58 degrees (answer in the books example). It's probably a simple issue with my geometry but I'm having trouble figuring it out and the book isn't too clear. Thanks.

http://imageshack.us/photo/my-images/43/33528972.jpg/

The exterior angle of a triangle is equal to the sum of the two interior, opposite angles.

D is the exterior angle to the triangle in the middle of the prism.

The left hand angle is 20o [40o + 30o + Xo = 90o]
The right hand angle is 50o - 12o

so 20o + 50o - 12o → 70o - 12o = 58o
 
I knew it was just me forgetting a geometry rule. Thank you for your help.
 

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