Question about the Stern-Gerlach Experiment

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The discussion centers on the Stern-Gerlach experiment and its relationship to quantum circuits. It clarifies that when a spin 1/2-particle passes through the Stern-Gerlach apparatus, it does not equate to applying a Hadamard transform unless specific conditions are met. The measurement direction of the magnetic field significantly influences the quantum circuit design; measuring along the z-axis requires only a measurement operation, while measuring along the x-axis necessitates Hadamard gates before and after measurement. The conversation also highlights the need for different circuit diagrams based on the measurement axis.

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captainhampto
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I have a general question about the Stern-Gerlach experiment. When a spin 1/2-particle passes through the magnets, is that effectively equivalent to applying a Hadamard transform to the state of the particle going through the apparatus?

Also, let's say I wanted to create a quantum circuit to reflect the Stern-Gerlach experiment. Would that basically be equivalent to:

H|q0> -> (measurement occurs) -> |q0> = |up> or |q0> = |down>
Untitled-1.png
 
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captainhampto said:
When a spin 1/2-particle passes through the magnets, is that effectively equivalent to applying a Hadamard transform to the state of the particle going through the apparatus?
Well, no. Could you elaborate on why you would think this?

Also, let's say I wanted to create a quantum circuit to reflect the Stern-Gerlach experiment. Would that basically be equivalent to:

H|q0> -> (measurement occurs) -> |q0> = |up> or |q0> = |down>
Untitled-1.png

Sort of. It depends on the direction of the magnetic field in the Stern-Gerlach apparatus. If the magnetic field points along the z-direction, then the Stern-Gerlach apparatus is measuring the spin along the z-axis, which is represented already by the "dial" symbol, so you should lose the Hadamard gate. If the magnetic field points along the x-axis, then you should be getting out particles with spin pointing along the +x or -x directions, so your circuit is still not quite right -- you need another Hadamard gate after the measurement.
 
Thanks again for the response cortiver, very much appreciated. So just for clarification, depending on the axis the Stern-Gerlach apparatus is measuring in, results in a differently constructed circuit?

So for the z-direction it is simply the measurement operation, the +x and -x require a Hadamard gate before and after the measurement? Also are there any specific papers/books that delve more into converting existing quantum mechanically based experiments into quantum computing analogies such as this one here (i.e. double slit experiment, interferometer, etc.)

Thanks again, I greatly appreciate the assistance.
 
captainhampto said:
Thanks again for the response cortiver, very much appreciated. So just for clarification, depending on the axis the Stern-Gerlach apparatus is measuring in, results in a differently constructed circuit?
Yes, measuring along different axes represents a different process, so obviously it needs a different circuit diagram to represent it. The "dial" symbol represents measurement along the z-axis -- you can get measurement along a different axis by combining with other gates, but you could also just define a new symbol to represent measurement along that axis.

So for the z-direction it is simply the measurement operation, the +x and -x require a Hadamard gate before and after the measurement? Also are there any specific papers/books that delve more into converting existing quantum mechanically based experiments into quantum computing analogies such as this one here (i.e. double slit experiment, interferometer, etc.)

Quantum computing deals with finite-dimensional quantum systems (e.g. spins). You can't represent continuous-space processes like two-slit interference in a quantum circuit diagram.
 

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