Question about Walter Brattain’s field-effect transistor principle.

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The discussion centers on Walter Brattain's field-effect transistor (FET) principle, specifically the observation that applying electrical contacts to a germanium crystal can yield an output power greater than the input. This phenomenon is explained through the operation of transistors, which function as amplifiers rather than power sources. The conversation highlights the importance of understanding semiconductor physics, particularly the roles of n and p-type semiconductors, as well as the concept of majority carrier inversion in FETs. Additionally, the discussion clarifies that the output power can exceed the input due to the combination of AC and DC signals in the circuit.

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  • Understanding of semiconductor physics, specifically n and p-type semiconductors
  • Familiarity with diode theory, including the concepts of electrons and holes
  • Knowledge of circuit theory and the operation of amplifiers
  • Basic grasp of field-effect transistor operation and its components
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  • Research "field effect transistor operation holes electrons" for a deeper understanding of FETs
  • Study "majority carrier inversion insulated gate" to comprehend the principles behind FETs
  • Explore the differences between FETs and BJTs (Bipolar Junction Transistors)
  • Investigate the historical development of transistors and their applications in modern electronics
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Question about Walter Brattain’s “field-effect transistor principle”.

The Wikipedia says “On 17 November 1947 John Bardeen and Walter Brattain observed that when electrical contacts were applied to a crystal of germanium the output power was larger than the input.“

Can someone please elaborate on how electrical contacts can be applied to a germanium crystal to make a power output larger than the input?

I don't see how you can get the current or the field to intensify just by putting a crystal inside a circuit.
 
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A transistor (effectively a switch or an amplifier) is very closely related to a pair of diodes (effectively one-way valves).

The simplest way to see this is to look up vacuum tube valves and then triodes.

Rather than using vacuum tubes, another way to produce these devices is by joining two types of crystal (see n and p semiconductors). A less intuitive way to get the same result is by using surface effects on a single crystal (see "point contact" or "cat's whisker" diodes and triodes).

Note here that a crystal amplifier works the same as a car stereo amplifier: the amplifier does not produce power (it just controls the flow of an applied power source, like a switch). But the technology is pretty cute: you can build a "foxhole radio" with nothing more than a rusty razor blade, a length of wire with a pointy end, and an earphone.

..as for the FET, wasn't that Shockley?
 
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How much semiconductor physics have you had? How about e/m field theory, circuit theory? You ask a broad question. It is hard to answer in a paragraph. The FET you refer to is explained all over the web. Search using the words "field effect transistor operation holes electrons". Also, you may include "majority carrier inversion insulated gate".

Are you reasonably familiar with diode theory of operation, i.e. electrons and holes? If not, I'd begin with that, and then work into transistors, FET or bjt. BR.

Claude
 
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If I remember correctly the material Lilienfeld used for his mesfet wasn't germanium nor silicon but cadmium sulfide. With it he was able to make an amplifier that inverted the input signal but unfortunately the gain was always less than 1.
 


skeptic2 said:
Lilienfeld [..] was able to make an amplifier that inverted the input signal but unfortunately the gain was always less than 1.
Seems like a typical use of the patent system: condemn everyone [else] to only using vacuum tubes for the next two decades ("for the good of society and progress").
 


Thanks for the response,

I understand that when you use a crystal amplifier that it just modulates the output of the power supply. I just don’t understand what they ment when they said…

“John Bardeen and Walter Brattain observed that when electrical contacts were applied to a crystal of germanium the output power was larger than the input.”

How can you have more output power than input power? That sounds like “overunity”. I guess this was just a typo?
 


A transistor has three contacts. One provides constant access to a large amount of power input. The next inputs a small amount of power in the form of a signal. The third is the signal output. By definition, the output signal must have more power than the input signal, or it wouldn't be an amplifier. There is no typo and no overunity, you're just forgetting about one of the three contacts.
 


Cyrus80772 said:
How can you have more output power than input power? That sounds like “overunity”. I guess this was just a typo?
Stating cesiumfrog's comment another way, you are also supplying a DC bias in addition to the AC signal. The AC output power is less than the sum of AC + DC input powers.
 
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in which field transistor is used widely
 

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