Question concerning the expected position of an object

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To determine the expected position of an object within a sphere of radius 5 meters from point P=(x_0,y_0,z_0), one must assume a specific probability distribution for the object within each shell defined by distances from P. If a spherically symmetric distribution is assumed, the expected coordinates of the object will be (0,0,0), particularly when P is also at the origin. The expected value remains at the origin due to the symmetry of the distribution, similar to how a symmetric distribution on a line centers around zero. Calculating the volume of each shell and setting the probability density function as p_i/v_i is essential for accurate computation. Ultimately, the expected coordinates depend on the symmetry of the probability distribution rather than the individual probability values.
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Suppose there's an object within a sphere of radius 5-metres from a given point P=(x_0,y_0,z_0). The probabilities of the object being within 0-1, 1-2, 2-3, 3-4 and 4-5 metres of P are given to be respectively p_1,p_2,p_3,p_4 and p_5. With this information, is it possible to find the expected position of the object,i.e, its expected coordinates?
 
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You would have to make a specific assumption about the probability distribution of the object within each of those "shells".
If you assume a distribution that is spherically symmetric about (0,0,0) in each shell, the expected coordinates of the object will be (0,0,0).
 
What kind of an assumption do I need? Could you give an example? Also, if P = (0,0,0), how do you get the expected coordinates of the object to be (0,0,0)? Doesn't it depend on the values of the probabilities of the object being within each shell?
 
Ryuzaki said:
What kind of an assumption do I need? Could you give an example?
Compute the volume v_i of each shell i = 1,2,3,4,5 and set the probability density function for the object within that shell to be p_i/v_i.

Also, if P = (0,0,0), how do you get the expected coordinates of the object to be (0,0,0)?

The expected value is (0,0,0) if the probability distributions are spherically symmetric. Think about a probability distribution on a line. If it is symmetric about x = 0 then the mean value of the distribution must be x = 0.
 
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