Question in (Conduction ) A steel plate 2 cm thick

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SUMMARY

The discussion centers on calculating the heat transfer through a 2 cm thick steel plate maintained at 550°C on one side and 50°C on the other. The thermal conductivity of stainless steel at 300°C is specified as 19.1 W/mK. The heat transfer equation used is q = -k . A . (dt/dx), leading to a calculated heat transfer rate of 477.5 W/m². However, participants noted discrepancies in the problem statement, indicating that the answer should be expressed "per unit area" and that the result may be off by a factor of 1000.

PREREQUISITES
  • Understanding of thermal conductivity and its units (W/mK)
  • Familiarity with the heat transfer equation q = -k . A . (dt/dx)
  • Basic knowledge of temperature gradients and their impact on heat transfer
  • Experience with unit conversions in thermal calculations
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  • Explore the concept of steady-state heat transfer and its calculations
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Mechanical engineers, thermal analysts, and students studying heat transfer principles will benefit from this discussion, particularly those involved in material science and thermal management applications.

manal950
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Hi

A steel plate 2 cm thick is maintained at a temperature of 550 C at one face and 50 C on the other .
The thermal conductivity of stainless stress at 300 C is 19.1 W/mK .

Compute the heat transferred through the material per unit length ?

Answer : -

we have q = - k . A . (dt/dx)

now
q = - k . (l.h) . (dt/dx)

q / (l.h) = -k( (dt/dx) )
= 477.5 w/m^2
 
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There is something wrong with the problem statement. It should be "per unit area". Also, it looks like the answer is off by a factor of 1000.
 
Pls explains your variables in the context of the problem.
 

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