Question inspired by reviewing conic sections

  • Context: Undergrad 
  • Thread starter Thread starter ScientificMind
  • Start date Start date
  • Tags Tags
    Conic sections
Click For Summary
SUMMARY

This discussion explores the mathematical properties of conic sections, specifically focusing on the conditions under which the product or quotient of distances to two foci remains constant. The user inquires about the existence of shapes or equations that satisfy the condition |AP| * |BP| = k, where A and B are the foci. The response clarifies that while ellipses and hyperbolas are defined by the sum and difference of distances, the proposed condition leads to a degree 4 polynomial equation in x and y. Additionally, the solution set for this equation is expected to yield closed curves, potentially representing new geometric shapes.

PREREQUISITES
  • Understanding of conic sections, specifically ellipses and hyperbolas.
  • Familiarity with distance formulas in a Cartesian coordinate system.
  • Basic knowledge of polynomial equations and their degrees.
  • Experience with contour plotting and visualizing mathematical functions.
NEXT STEPS
  • Research the properties of degree 4 polynomial equations in two variables.
  • Explore contour plotting techniques for visualizing complex mathematical functions.
  • Investigate the geometric interpretations of products and quotients of distances in conic sections.
  • Learn about the implications of constant product conditions in higher-dimensional geometry.
USEFUL FOR

Mathematicians, calculus students, and educators interested in advanced properties of conic sections and their geometric implications.

ScientificMind
Messages
48
Reaction score
1
Recently, in my calculus two class, we began going over conic sections. After reviewing the definitions of ellipses and hyperbolas - For two given points, the foci, an ellipse is the locus of points such that the sum of/difference between the distance to each focus is constant, respectively - I couldn't help but become curious: does a shape and/or equation for a set of points such that "the product or quotient of the distance to each focus is constant" instead of just the sum or difference? I posed this question to my math instructor too, but he didn't know. (I hope that this is the right section to post this in. It seemed most likely, but I couldn't tell with any certainty which sub-forum to post this on)
 
Mathematics news on Phys.org
Can you explain precisely what you mean? If I consider two points ##A,B## at a distance ##a,b## form a focus ##F##, i.e. ##a=|AF| , b=|BF|## and look out for a third point ##C## with distance ##c=|CF|## from the focus, such that ##ab=ac=bc##, then I get ##a=b=c## and end up with a circle or the set ##\{A,B,F\}##.
 
fresh_42 said:
Can you explain precisely what you mean? If I consider two points ##A,B## at a distance ##a,b## form a focus ##F##, i.e. ##a=|AF| , b=|BF|## and look out for a third point ##C## with distance ##c=|CF|## from the focus, such that ##ab=ac=bc##, then I get ##a=b=c## and end up with a circle or the set ##\{A,B,F\}##.
First of all, ellipses and hyperbolas both have two foci, not one focus. The two foci are the two points in the definitions I provided, not two other points. So, if the two foci are A and B, and the distances between those foci and any given point P are |AP| and |BP|:
An ellipse (represented by the equation (x2/a2) + (y2/b2) = 1, or (y2/a2) + (x2/b2) = 1 with a>b) consists of all points P such that |AP| + |BP| is constant and a hyperbola (represented by the equation (x2/a2) - (y2/b2) = 1, or (y2/a2) - (x2/b2) = 1) consists of all points P such that the absolute value of |AP| - |BP| is constant. What I'm asking is if there are any shapes and equations for the sets of points such that |AP| * |BP| is constant, |AP| / |BP| is constant, and/or |BP| / |AP| is constant.
 
ScientificMind said:
What I'm asking is if there are any shapes and equations for the sets of points such that |AP| * |BP| is constant, |AP| / |BP| is constant, and/or |BP| / |AP| is constant.
Are there equations? Of course. ##k = |AP| \cdot |BP|## is an equation. It could be written as ##k = \sqrt{(x-x_A)^2 + (y-y_A)^2} \cdot \sqrt{(x-x_B)^2 + (y-y_B)^2}##

Are you, perhaps, asking whether that equation could be simplified into some other form such as a polynomial equation in x and y using some constants which depend on k, ##\vec{A}## and ##\vec{B}##? It looks like squaring both sides would be a good start. I've not worked it out, but it looks like that particular result would be a degree 4 polynomial equation in x and y.

Are there shapes? Of course. You could plot the solution set for the above equation. I believe the solution set (for k>0, and ##\vec{A}## different from ##\vec{B}##) will always contain at least one and possibly two closed curves. Are you, perhaps, asking whether those curves are shapes which are well-known by other names? Beats me.
 
Last edited:
  • Like
Likes   Reactions: SlowThinker and ScientificMind
jbriggs444 said:
Are there equations? Of course. ##k = |AP| \cdot |BP|## is an equation. It could be written as ##k = \sqrt{(x-x_A)^2 + (y-y_A)^2} \cdot \sqrt{(x-x_B)^2 + (y-y_B)^2}##

Are you, perhaps, asking whether that equation could be simplified into some other form such as a polynomial equation in x and y using some constants which depend on k, ##\vec{A}## and ##\vec{B}##? It looks like squaring both sides would be a good start. I've not worked it out, but it looks like that particular result would be a degree 4 polynomial equation in x and y.

Are there shapes? Of course. You could plot the solution set for the above equation. I believe the solution set (for k>0, and ##\vec{A}## different from ##\vec{B}##) will always contain at least one and possibly two closed curves. Are you, perhaps, asking whether those curves are shapes which are well-known by other names? Beats me.
:-pYeah, I suppose it was kind of a silly way for me to phrase my questions. Though I commend you for not only answering the questions I posed but also addressing and answering the questions I meant when I myself didn't fully realize that those alternate questions were far closer to expressing what I was actually curious about. Thank you
 
If you make a contour plot of ##z = \sqrt{(x-x_A)^2 + (y-y_A)^2} \cdot \sqrt{(x-x_B)^2 + (y-y_B)^2}##, you should be able to see what the level curves look like.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 4 ·
Replies
4
Views
14K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 2 ·
Replies
2
Views
6K
  • · Replies 3 ·
Replies
3
Views
5K