Question (Mechanics of Materials)

[Sajama66]

Hi guys, I am attaching a pdf file with the respective question it might be silly for many of you, but I would rather this question now, and move on with the problem.
The pdf file is from a class from mechanics of materials, I understand the procedure and how formulas are plugged and how the problem is solved, but I don't understand how the distributed load (150 kN/m changed to 90 kN) the instructor at class didn't want to answer and evade the question. (I circled the slide with the doubt about the load)
Your answer will be very helpful to clarify my basic knowledge of this class.
Thanks in advance
keep the great work

 

[PhanthomJay]

The distributed load of 150kN/meter over the 0.600m length of the rigid bar yields a total resultant load of (150kN/m)*(0.600m) = 90kN. Thus, the distributed load of 150 kN/m over the 0.6m length is represented as a concentrated load of 90kN at the centroid of the rigid bar.

 

[piercas]

Dear student,

Thank you for reaching out and seeking clarification on this question. It is important to fully understand all aspects of a problem in order to effectively solve it.

In regards to the change in distributed load from 150 kN/m to 90 kN, it is possible that the instructor wanted to challenge the class to think critically and apply their knowledge in a different way. It is also possible that the change in load was made to make the problem more realistic or applicable to a real-life scenario.

In any case, the key to solving this problem is to understand the concept of distributed load and how it affects the overall load on a structure. I suggest reviewing your notes and the textbook to gain a better understanding of this concept.

If you are still unsure, I encourage you to approach your instructor again and ask for clarification. it is important to always seek understanding and continuously learn. Do not be afraid to ask questions and seek help when needed.

I wish you all the best in your studies and hope this response has been helpful.