Question on calculating load on tidal movement

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  • Thread starter Thread starter jamesd442001
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    Load Movement Tidal
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Discussion Overview

The discussion revolves around calculating the load on tidal movement, specifically exploring the relationship between wind load and water load, and the implications of fluid mechanics in these calculations. The scope includes theoretical aspects of fluid dynamics and practical applications in engineering.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant presents a formula for calculating wind load and questions whether it can be adapted for water load by multiplying by the density difference between air and water.
  • Another participant provides a more general equation for turbulent flow force calculations, emphasizing the importance of using the correct coefficient for different force components.
  • A participant expresses a desire for a concise answer and indicates previous unsuccessful attempts to obtain clarity from consulting engineers.
  • A later reply states that directing participants to external services for answers is not permitted on the forum.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the applicability of the wind load formula to tidal movement calculations, and there are competing views on how to approach the problem.

Contextual Notes

There are limitations in the discussion regarding the assumptions made in the calculations, the dependence on the correct coefficients in fluid mechanics, and the potential variations in water density under different atmospheric conditions.

jamesd442001
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Calculating wind load is windspeed x itself x.00431 x sq. ft. of area. A 100 sq.ft vertical wing in a five mph wind is 10.77 lbs. The mass of salt water is around 854 times that of air. Can you use the wind formula and multiply by 854? Also, does this change with the weight of water at different atmospheres?
 
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The basic equation you are describing is
F = (1/2)*rho*C*V^2
which is used for all sorts of turbulent flow force calculations. The trick is to have the correct C for the force component you want to calculate. It is common to distinguish between a lift and a drag force component, where each has its own coefficient (C-value).

I suggest you do some reading on fluid mechanics before you try to make these calcs to be sure you know what you are doing.
 
I'm more of a mechanical individual looking for the short answer at this point. There is quite a bit more to this than I'm showing. I,ve engaged several consultant engineers at this point to no avail. So if there is not a short answer can you direct me to someone or a service capable of the short and long answer?
 
Unfortunately, no. That is not permitted on this forum.
 

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