Question on Equivalent/Hydraulic Diameter

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SUMMARY

The discussion focuses on calculating the equivalent or hydraulic diameter (D_h) for a closed rectangular flow area. The formula used is D_h = 4*A_x-section/P_wetted. The user calculated the cross-sectional area (A_x-section) as 18 cm² and the wetted perimeter (P_wetted) as 42 cm, resulting in a hydraulic diameter of 1.714 cm (0.01714 m). The calculations are confirmed as correct based on the provided dimensions and formula.

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Homework Statement


Hello, I have a question on how to calculate the equivalent/hydraulic diameter for a problem that I'm doing.

The problem states that I should use the cross-sectional flow area shown with an equivalent diameter based upon a closed rectangle (entire perimeter)

[PLAIN]http://img196.imageshack.us/img196/3968/finsm.jpg


Homework Equations



D_h = 4*A_x-section/P_wetted


The Attempt at a Solution




So I did:

A_xsection = 6cm * 1cm = 6cm^2
Since there are three slits, I multiplied that by 3 to get: 18cm^2

The perimeter was 6+6+1+1 = 14cm
I also multiplied this by 3 to get: 42cm


D_h = 4*(18cm^2)/42cm = 1.714 cm = 0.01714 m


Is this right?
 
Last edited by a moderator:
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Looks OK to me.
 

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