Psi question about a hydraulic cylinder

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SUMMARY

The discussion focuses on calculating the effective diameter and maximum velocity of a hydraulic cylinder in a log splitter operating at 3000 psi with a 5 hp hydraulic engine. The effective diameter was determined to be 2.91 inches (0.0739 meters) using the formula F=(p*pi*d^2)/4, where F is the force and p is the pressure. To find the maximum velocity, the relationship Power = Force * Velocity is applied, but the user struggled to derive the correct velocity due to unit inconsistencies.

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Homework Statement


A hydraulic log splitter with a maximum operating pressure of 3000 psi is powered by a 5 hp hydraulic engine. If the log splitter is capable of generating a maximum nominal force of 10 tons (20000 lb) what is the effective diameter of the hydraulic cylinder? What is the maximum velocity of the cylinder when the opposing force is 10 tons?

Homework Equations


F=(p*pi*d^2)/4
http://citeseerx.ist.psu.edu/viewdo...1DD4503?doi=10.1.1.269.7079&rep=rep1&type=pdf[/B]

The Attempt at a Solution



Part 1)[/B]
Using equation above,
20000LB=(3000 psi * pi * d^2 )/4
d=2.91 inches

Part 2)
Not sure how to calculate speed. I tried calculating...
2.91 inches to meter = 0.0739 m

pi * 0.0739^2/4= 0.00429 m/s

I'm using the website above as a source and I don't see any formulas for speed. I tried calculating it but I can't get the right answer.
 
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The equation used in the example on the second to last page (Power = Force * Velocity) is what you need.
You have two of the variables so you can solve for velocity. As always, make sure your units are consistent.
 

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