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Homework Help: Hydraulic diameter vs hydraulic radius

  1. Mar 6, 2016 #1
    1. The problem statement, all variables and given/known data
    i was told that the hydraulic diameter = 4Ac / p , while the hydraulic radius = Ac / p , where Ac = cross sectional area , and p = wetted perimeter of the pipe , why shouldn't the hydraulic radius = 2Ac / p ?
    because as well all know , diameter = 2 Radius , so hydraulic radius = 2(hydraulic diameter ) = 2(4Ac / p) = 8Ac / p

    2. Relevant equations

    3. The attempt at a solution

    Attached Files:

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  2. jcsd
  3. Mar 6, 2016 #2
    It doesn't make sense, but this is the terminology that's used. So learn to live with it.

    Your mathematics here is incorrect.
  4. Mar 6, 2016 #3


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