Question on gravitation law derivation

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The forum discussion centers on the derivation of Newton's Universal Law of Gravitation, specifically the mathematical ratios involved in understanding the relationship between angular velocity (ω), linear velocity (ν), distance (s), and orbital period (T). The user seeks clarification on the initial steps of the derivation, particularly the limits and ratios presented. Key ratios discussed include ω/ν = s/r and t/T = s/(2πr), which illustrate how changes in time and distance relate to each other in the context of orbital mechanics.

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Thiafon
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Hi, guys.
I was wondering on Newton's Gravity Law derivation, and I found this page: http://www.relativitycalculator.com/Newton_Universal_Gravity_Law.shtml
Everything seems clear, but the first step is just killing me, because I can't get it.
Assuming small incremental changes in s; <br /> \lim_{t\rightarrow 0} {s} \rightarrow 0<br />
we have the following ratios
\frac{\omega}{\nu}=\frac{s}{r}, and \frac{t}{T}=\frac{s}{2πr}
Could someone help me out? Explain, or just say, which part of math do I have to cover in order to understand that?
(btw, I did pre-calculus, and calculus, so concept of limits is familiar to me)
Thanks in advance.
 
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It's just telling you the ratios of everything. The vector changes at the same rate that the distance traveled does since v and r are equal. If you double w you double s as well.

In the 2nd ratio, T is the total time of one orbital period and 2*Pi*R is the total distance of the orbit. As t changes, which is the time it takes to transverse the incremental time period s, s changes as well. If you double t you double s. Does that make sense?
 
Yes, thank you a lot! I had kind of intuitive feeling about it, but I wasn't sure if it is correct.
 

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