Question on heat transfer of a plane wall

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SUMMARY

The discussion focuses on calculating the rate of heat conduction through a plane wall with a thickness of 152 mm and a surface area of 2.32 m², where one side is maintained at 82.2 °C and the other at 4.4 °C. The thermal conductivity values provided are 0.036 W/m·K at 0 °C and 0.055 W/m·K at 93.3 °C. To find the rate of heat conduction, users must estimate the thermal conductivity at the average temperature between the two surfaces. The equation Q = ∆T/R is essential for this calculation, where R is the thermal resistance.

PREREQUISITES
  • Understanding of heat transfer principles
  • Familiarity with thermal conductivity concepts
  • Knowledge of the equation Q = ∆T/R
  • Basic skills in temperature averaging
NEXT STEPS
  • Research how to calculate thermal resistance in heat conduction problems
  • Learn about the temperature dependence of thermal conductivity
  • Explore practical applications of Fourier's law of heat conduction
  • Study the impact of wall thickness on heat transfer rates
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Students in thermal engineering, mechanical engineers, and anyone involved in building design or energy efficiency analysis will benefit from this discussion.

sero2000
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Homework Statement



A plane wall of 152 mm thickness has surface area of 2.32 m2. One side of the wall is kept at 82.2 oC, and the other side at 4.4 oC. The thermal conductivity of the wall material is 0.036 W/m.K at 0 oC, and that at 93.3 oC is 0.055 W/m.K. Calculate the rate of heat conduction through the wall

Homework Equations



Q= ∆T/R

The Attempt at a Solution



I do understand how to do this but i gt stuck at the part of the question that says "The thermal conductivity of the wall material is 0.036 W/m.K at 0 oC, and that at 93.3 oC is 0.055 W/m.K"

Anyone can just explain to me what does it mean?
 
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That means you should estimate the thermal conductivity at your required temperatures
 

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