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Archived Heat transfer calculation across a flat plate

  • Thread starter tcaldwell
  • Start date
7
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Heat Transfer Qts
Engine oil at 60 oC flows over flat plate whose temperature is at 20 oC with a velocity of 2 m s-1. The length of the plate is 5m. What is the film temperature and the rate of heat transfer per unit width of the entire plate?
Additional information (at the film temperature):
Thermal conductivity of oil: Prandtl number:
Dynamic viscosity:
k1 = 0.144 W m-1 K-1
Pr = 2870
u = 0.21 kg m-1 s-1

Help!!!!!!
Can't get a Reynolds number without density..
Is film temperature 40 degrees Celsius????
 
228
53
First, the film temperature is
[tex]T_f = \frac{T_{\infty} + T_S}{2} = 40 °C[/tex]
Now, I'm almost certain this is a problem from Incropera's heat transfer book, so I got the density of the oil at Tf from table A.5 (Incropera). The values of k, Pr and μ also coincide with the values in the table for Tf. Now, calculating the average Reynolds number for a flat plate
[tex]\textrm{Re} = \frac{\rho v L}{\mu} = \frac{\left(876.07 \frac{kg}{m^3} \right) \left(2 \frac{m}{s} \right)(5 \ m)}{0.21 \frac{kg}{m \cdot s}} = 41717.62[/tex]
For a flat plate, Re < 500000 indicates laminar flow. Now we use the following correlation for the average Nusselt number for laminar flow over a flat plate (applies for all Pr ≥ 0.6)
[tex]\textrm{Nu} = 0.664 \ \textrm{Re}^{\frac{1}{2}} \ \textrm{Pr}^{\frac{1}{3}} = 0.664 (41717.62)^{\frac{1}{2}} (2870)^{\frac{1}{3}} = 1927.326[/tex]
Now we can calculate the average heat transfer coefficient using the Nusselt number
[tex]h = \frac{\textrm{Nu} \ k}{L} = 1927.326 \frac{0.144 \frac{W}{m \cdot K}}{5 \ m} = 55.5 \frac{W}{m^2 \cdot K}[/tex]
Finally, we calculate the rate of heat transfer per unit width of plate
[tex]q' = hL(T_{\infty} - T_S) = \left(55.5 \frac{W}{m^2 \cdot K} \right) (5 \ m) (60 °C - 20 °C) = 11100 \frac{W}{m}[/tex]
 

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